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ryzh [129]
3 years ago
14

Help asap. How many moles are 5.55x10^25 atoms of Mg

Chemistry
1 answer:
LekaFEV [45]3 years ago
3 0

Answer:

\boxed {\boxed {\sf About \ 92.2 \ moles \ of \ Magnesium}}

Explanation:

To convert from atoms to moles, we must Avogadro's number:

  • 6.022*10²³

This number tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, it is atoms of magnesium in 1 mole.

  • 6.022 *10²³ atoms Mg / 1 mol mg

Now, let's set up an expression using:

\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}

Multiply this by the given number of atoms.

5.55*10^{25} \ atoms \ Mg *\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}

Flip the fraction so the atoms of magnesium can cancel.

5.55*10^{25} \ atoms \ Mg *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23} \ atoms \ Mg}

5.55*10^{25} *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23}}

Multiply and condense this into 1 fraction.

\frac { 5.55*10^{25} \ mol \ Mg }{6.022 * 10^ {23}}

92.1620724 \ mol \ Mg

The original measurement had 3 significant figures, so our answer must have that many as well. For the number we calculated, that is the tenth place. The 6 in the hundredth place tells us to round the 1 to a 2.

92.2 \ mol \ Mg

It is about <u>92.2 moles of magnesium.</u>

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How many Calcium (CA) atoms are in carbon tetrachloride​
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Answer:

5

Explanation:

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Sequence the following types of waves from lowest frequency to highest frequency: ultraviolet rays, infrared rays, gamma rays, r
7nadin3 [17]
Light Spectrum:

Gamma Rays; X- Rays; Ultraviolet Rays; Infrared; Micro; Radio

I'm guessing green means the color wave 
So it should be: Radio-Infrared- Green - UV - Gamma 
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3 years ago
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0.378g grams of a compound is made up of 0.273g of Mg and 0.105g nitrogen. Find its empirical formula.
Harrizon [31]

Answer:

The empirical formula of the compound is Mg_3N_2.

Explanation:

Mass of magnesium in compound = 0.273 g

Mass of nitrogen in the compound = 0.105 g

Moles of magnesium =\frac{0.273 g}{24.305 g/mol}=0.0112 mol

Moles of nitrogen = \frac{0.105 g}{14.0067 g/mol}=0.00750 mol

Form empirical formula divides the lowest value of moles of an element present with all the moles of elements present.

Magnesium =\frac{0.0112 mol}{0.00750 mol}=1.5

Nitrogen =\frac{0.00750mol}{0.00750 mol}=1

The empirical formula of a compound:

Mg_{1.5}N_1=Mg_{\frac{15}{10}}N_1=Mg_{15}N_{10}=Mg_3N_2

The empirical formula of the compound is Mg_3N_2.

3 0
3 years ago
The discharge of chromate ions (CrO42-) to sewers or natural waters is of concern because of both its ecological impacts and its
muminat

Answer:

45727g

Explanation:

So, have the overall ionic equation given as the following;

CrO42^- + 3 Fe2^+ + 8 H2O ------> Cr(OH)^3(s) + 3 Fe(OH)^3(s) + 4 H^+.

So, we have (from the question) that the amount or quantity of the waste stream daily = 60m^3/h, and the waste stream daily contains waste stream containing = 4.0 mg/L Cr, and the discharge limit = 0.1 mg/L.

Step one: convert m^3/ h to L/h. Therefore, 60 m^3/h × 1000dm^3 = 60000 L/h .

Step two: Determine or calculate the the value of Cr used up.

The value of Car used up ={ 60,000 × ( 4.0 - 0.1) } ÷ 1000 = 234 g.

Step three: Determine or calculate the mass of Cr(OH)3 and the mass of Fe(OH)3.

The number of moles of Cr = 234/52 = 4.5 moles.

Molar mass of Cr(OH)3 = 103 g/mol and the molar mass of Fe(OH)3 = 106.8 g/mol.

Thus, the mass of Cr(OH)3 = 4.5 × 103 = 463.5 g.

And the mass of Fe(OH)3 = 13.5 × 106.8 = 1441.8 g.

Hence, the total = 463.5 g + 1441.8 g = 1905.3 g.

Step four: Determine or calculate the How much particulate matter would be generated daily.

The amount of the particulate that would be generated daily = 24 × 1905.3 = 45727g.

7 0
3 years ago
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