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ryzh [129]
3 years ago
14

Help asap. How many moles are 5.55x10^25 atoms of Mg

Chemistry
1 answer:
LekaFEV [45]3 years ago
3 0

Answer:

\boxed {\boxed {\sf About \ 92.2 \ moles \ of \ Magnesium}}

Explanation:

To convert from atoms to moles, we must Avogadro's number:

  • 6.022*10²³

This number tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, it is atoms of magnesium in 1 mole.

  • 6.022 *10²³ atoms Mg / 1 mol mg

Now, let's set up an expression using:

\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}

Multiply this by the given number of atoms.

5.55*10^{25} \ atoms \ Mg *\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}

Flip the fraction so the atoms of magnesium can cancel.

5.55*10^{25} \ atoms \ Mg *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23} \ atoms \ Mg}

5.55*10^{25} *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23}}

Multiply and condense this into 1 fraction.

\frac { 5.55*10^{25} \ mol \ Mg }{6.022 * 10^ {23}}

92.1620724 \ mol \ Mg

The original measurement had 3 significant figures, so our answer must have that many as well. For the number we calculated, that is the tenth place. The 6 in the hundredth place tells us to round the 1 to a 2.

92.2 \ mol \ Mg

It is about <u>92.2 moles of magnesium.</u>

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Answer:

Primary carbocations are most stable, Secondary carbocations are more stable, tertiary carbocations are least stable.

Explanation:

This is due to Asterric hinderance.

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3 years ago
<img src="https://tex.z-dn.net/?f=plz%20%5C%3A%20help%20%20%5C%3A%20me%20%5C%3A%20it%20%5C%3A%20is%20%5C%3A%20due%20%5C%3A%202mo
Sophie [7]

Answer:

hi.

Explanation:

1. B

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5 0
3 years ago
In which time period did alchemists attempt to change less valuable metals into gold? 8000 BC – 1000 BC 1000 BC – 450 BC 300 BC
SSSSS [86.1K]
Time Period 3 (300 BC to 1400 AD)

The alchemists were in pursuit of 2 ideals. First, alchemy came about from the belief that cheap metals can be transmuted to gold using the legendary substance <em>Philosopher's Stone</em> for the conversion. These views were greatly influenced by Aristotle. Thus, from 300 BC to 1400 AD, alchemists worked to make the conversion of cheap metals to gold a reality. However, it never succeeded. 

After this, the second ideal that the alchemists were in pursuit of was the concoction of an elixir of life to enable people to live longer and cure all ailments. This took place in the 1500s up to the end of the 1600s. Just like the pursuit of the first ideal, efforts to succeed in the second one all led to failure. 
5 0
3 years ago
In a sample containing 100 atoms of X, 70 were found to be 9X while 30 were 11X isotopes. Determine the average relative atomic
Burka [1]

The average relative atomic mass of a sample containing 100 atoms of X, 70 were found to be 9X while 30 were 11X isotopes is 9.6g.

<h3>What is Atomic mass? </h3>

Atomic mass is defined as the whole mass of an atom.

It is also defined as the sum of atomic number and number of neutrons.

Atomic mass = Atomic number + neutrons

<h3>What is Isotopes?</h3>

Isotopes are the those element which have same atomic number but have different mass number and number of neutrons.

The average relative atomic mass can be calculated as

mass of isotopes/ mass of sample

mass of all isotopes = (70 × 9X) + (30 × 11X)

=(630 + 330) X

= 960X

Average relative atomic mass = 960X/ 100 X

= 9.6 g

Thus, we concluded that the average relative atomic mass of a sample containing 100 atoms of X, 70 were found to be 9X while 30 were 11X isotopes is 9.6g.

learn more about atomic mass:

brainly.com/question/14250653

#SPJ9

5 0
2 years ago
Please help! What is the molarity of 450 mL of solution containing 15 g NaCl?
siniylev [52]

Answer:

The answer to your question is 0.6 M

Explanation:

Data

Molarity = ?

Volume = 450 ml

mass of NaCl = 15 g

Process

1.- Calculate the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5 g

2.- Calculate the number of moles of NaCl

             58.5 g of NaCl ------------ 1mol

                 15 g of NaCl ------------   x

                         x = (15 x 1)/58.5

                         x = 0.26 moles

3.- Calculate the molarity

Molarity = moles/volume

-Substitutiion

Molarity = 0.26/0.45l

-Result

Molarity = 0.6 M

7 0
4 years ago
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