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NikAS [45]
3 years ago
11

Give the effect on the melting point of the presence of a cis double bond in a fatty acid.

Chemistry
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

The cis double bond present in unsaturated fatty acids acids results in lower melting point when compared to saturated fatty acids of the same chain length.

Explanation:

Melting point of a fatty acids are affected by the length and degree of unsaturation of the hydrocarbon chain.

At room temperature, saturated fatty acids with hydrocarbon chain lengths between 12-24 are waxy solids whereas unsaturated atty acids of the same chain length are liquids. This is due to the nature of the packing of the fatty acid molecules in the saturated and unsaturated compounds.

In the saturated compounds, the molecules are tightly packed side by side with minimal steric hindrance and maximal van der Waals forces of attraction between molecules. However, in unsaturated fatty acids, the cis double bond introduces a bend or kink in the molecules which then interferes with the tight packing of the molecules and reducing interaction between molecules. Therefore, less energy is required to cause a disorder in the arrangement of unsaturated fatty acids, leading to a lowering of melting point.  

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\text{mass MgCl}_2=massbeakerwithMgCl_2-mass\text{ emprty beaker =37.83 g - 33.95g = 3.8}8g

7 0
1 year ago
Which part of the food web is NOT a living thing?
stiks02 [169]

Answer:

the sun

Explanation:

the sun is not alive and plants use photosynthesis to eat the radiation emitted by the sun.

4 0
3 years ago
Select the correct answer from each drop-down menu. In a voltaic cell, the electrons and is oxidized, while the electrons and is
KengaRu [80]

Given what we know, we can confirm that in a voltaic cell, the anode loses electrons and is oxidized, meanwhile, the cathode is reduced by gaining electrons.

<h3 /><h3>What is a voltaic cell?</h3>
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Therefore, given the nature of the voltaic cell, we can confirm that during its reaction, the anode is oxidized by losing electrons while the cathode becomes reduced by gaining them.

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3 0
2 years ago
Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
coldgirl [10]

Answer:

\rm_{90}^{231}\text{Th}

Explanation:

The unbalanced nuclear equation is

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + X

Let's write X as a nuclear symbol.

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

 92 = 2 + Z , so  Z =   92 - 2 =  90

And your nuclear equation becomes

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} +\, _{90}^{231}\text{X}

Element 90 is thorium, so  

\rm X = _{90}^{231}\text{Th}

7 0
3 years ago
Calculate the number of grams of nitrogen dioxide that are produced from 4 moles of nitric oxide
miv72 [106K]

Answer:

hope this help by the way found off of yahoo

Explanation:

Calculate the number of grams of nitrogen dioxide that are produced from

4 moles of nitric oxide.

2NO(g) + O2(g) -->2NO2(g)

I really need help with this... I need to know how to work it too... I can balance it out but not sure about grams...  This is it balanced out with 4 moles of nitric oxide

4NO(g) + 2O2(g) ->4NO2(g) please help and explain i want to learn this

6 0
3 years ago
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