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rodikova [14]
3 years ago
12

How many moles are in 12.5 g ammonium chloride

Chemistry
1 answer:
77julia77 [94]3 years ago
3 0

Answer:

0.233682161601125

Explanation:

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What is the mass (in grams) of 9.93 Ă— 1024 molecules of methanol (CH3OH)?
WINSTONCH [101]

Answer is: mass of methanol is 528.32 grams.

N(CH₃OH) = 9.93·10²⁴; number of methanol molecules.

n(CH₃OH) = N(CH₃OH) ÷ Na (Avogadro constant).

n(CH₃OH) = 9.93·10²⁴ ÷ 6.022·10²³ 1/mol.

n(CH₃OH) = 16.49 mol; amount of substance.

m(CH₃OH) = n(CH₃OH) · M(CH₃OH).

m(CH₃OH) = 16.49 mol · 32.04 g/mol.

m(CH₃OH) = 528.32 g.

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3 years ago
What occurs when the moon's shadow hits Earth or Earths shadow hits the moon
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A lunar eclipse i think
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A 24.00 mL sample of a solution of Pb(ClO3)2 was diluted with water to 52.00 mL. A 17.00 mL sample of the dilute solution was fo
klio [65]

Answer:

0.238 M

Explanation:

A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.

C₁.V₁ = C₂.V₂

C₁ × 24.00 mL = 0.220 M × 52.00 mL

C₁ = 0.477 M

The concentration of Pb(ClO₃)₂ is:

\frac{0.477molClO_{3}^{-} }{L} \times \frac{1molPb(ClO_{3})_{2}}{2molClO_{3}^{-}} =0.238M

4 0
3 years ago
Which of the following summertime activities consists solely of physical change?
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A: making s sandcastle. This is because water and sand is only a mixture, so they do not react with each other. All the rest include chemical reactions!
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3 years ago
What is the mole fraction of NaCl in a mixture containing 7.21 moles NaCl, 9.37 moles KCL, and 3.42
GrogVix [38]

Answer : The mole fraction of NaCl in a mixture is, 0.360

Explanation : Given,

Moles of NaCl = 7.21 mole

Moles of KCl = 9.37 mole

Moles of LiCl = 3.42 mole

Now we have to calculate the mole fraction of NaCl.

\text{Mole fraction of }NaCl=\frac{\text{Moles of }NaCl}{\text{Moles of }NaCl+\text{Moles of }KCl+\text{Moles of }LiCl}

Now put all the given values in this formula, we get:

\text{Mole fraction of }NaCl=\frac{7.21}{7.21+9.37+3.42}=0.360

Therefore, the mole fraction of NaCl in a mixture is, 0.360

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3 years ago
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