Sedimentary rocks have layers because of different depositions of sediments over time.
Answer:
The correct answer is option 3.
Explanation:

The expression of
is given by :
![K_w=[H^+][OH^-]](https://tex.z-dn.net/?f=K_w%3D%5BH%5E%2B%5D%5BOH%5E-%5D)
![K_w\propto [H^+]](https://tex.z-dn.net/?f=K_w%5Cpropto%20%5BH%5E%2B%5D)
![K_w\propto [OH^-]](https://tex.z-dn.net/?f=K_w%5Cpropto%20%5BOH%5E-%5D)
Rise in temperature will result in more dissociation of water molecules into hydrogen ions and hydroxide ions.
With an increase in concentration of hydrogen ions and hydroxide ions value of
will also increase.
The correct answer for the question that is being presented above is this one: "B) Temperature."
Here are the following choices:
A) all of these measurements are needed
B) Temperature
C) Molar Mass
D) Pressure
E) Mass
So if we use the equation:
→ 
We can then determine the amount of
needed to produce 208 kg of methanol.
So let's find out how many moles of methanol 208 kg is:
Methanol molar weight = 32.041g/mol
So then we can solve for moles of methanol:

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.
Therefore, we can set up a proportion to solve for the moles of hydrogen needed:


So now that we have the number of moles of
that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:

Therefore, the amount of diatomic hydrogen (
) that is needed to produce 208kg of methanol is
g.
Answer:
The increasing order of masses of molecule ions:
118 g/mol(75.8%) , 120 g/mol(24.2%)
Explanation:
Chlorine occurs as 35-Cl (75.8%) and 37-Cl (24.2%).
Atomic mass of 35-Cl = 35 g/mol
Atomic mass of 37-Cl = 37 g/mol
Mass of Chlorocyclohexane in which 35-cl is present as a chlorine atom: 

Mass of Chlorocyclohexane in which 37-Cl is present as a chlorine atom: 

The increasing order of masses of molecule ions:
118 g/mol(75.8%) < 120 g/mol(24.2%)