The diagram shows the position
1 answer:
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Since the sum of the numbers on the three draws is 12, if we want the card numbered 2 to be drawn exactly two times, the third card can only be numbered 8. In fact, , and there are no other possibilities, unless you consider the various permutations of the terms.
So, we have three favourable cases: we can draw 2,2,8, or 2,8,2, or 8,2,2. This are the only three cases where the card numbered 2 is drawn exactly two times, and the sum of the number on the three draws is 12.
Now, the question is: we have three favourable cases over how many? Well, we have 5 possible outcomes with each draws, and the three draws are identical, because we replace the card we draw every time.
So, we have 5 possible outcomes for the first draw, 5 for the second and 5 for the third. This leads to a total of possible triplets.
Once we know the "good" cases and the total number of possible cases, the probability is simply computed as
Answer:
For this transition of equations, the graph of g(x) will be translated left 2 units with respect to the graph of f(x), so your answer choice will be A.
Step-by-step explanation:
In this equation, g(x) is changed by adding 2 and closing part of the equation in parenthases, this results in the translation 2 units left, which can be proven by a graph and my answer.
