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3 years ago

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A box of crayons costs $1.75, including tax. Mr. Valentino wants to purchase boxes of crayons for his class and has a $25 budget

. Write an inequality to solve for the number of boxes of crayons Mr. Valentino can purchase with his budge

1 answer:

Vlada [557]3 years ago

7 0

Answer:

1.75x ≤ 25. Hope this helps

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Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel

serious [3.7K]

Complete Questions:

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.

a. 40

b. 48

c. 56

d. 64

Answer:

a. 0.35

b. 0.43

c. 0.49

d. 0.54

Step-by-step explanation:

(a)

The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.

Let s be the sample space of all integer not exceeding 40.

The total number of ways to select 6 numbers from 40 is $|S| = C(40,6)$ .

Let E be the event of selecting none of the correct six integers.

The total number of ways to select the 6 incorrect numbers from 34 numbers is:

$|E| = C(34,6)$

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is

$P(E) = \frac{|E|}{|S|}$

$= \frac{C(34, 6)}{C(40, 6)}\\\\= \frac{1344904}{3838380}\\\\=0.35$

Therefore, the probability is 0.35

Check the attached files for additionals

8 0

3 years ago

Yale is working out 2 hours in a gym. If he spends 21 minutes on stretching and 45 minutes of Jogging. What percentage of time d

MArishka [77]

54% of the time. 21 and 45 is 66. Two hours is 120. The you subtract

6 0

3 years ago

What is the value of the expression shown? 4(-2) + (-10) + 3(-8)

Vlad [161]

Answer:

-42

Step-by-step explanation:

1. 4(-2)

2. 3(-8)

3. -8 + -10 + -24

4. cobine like terms

5. -42

7 0

2 years ago

A teacher claims that the proportion of students expected to pass an exam is greater than 80%. To test this claim, the teacher a

erica [24]

Answer:

z=-1.591

Step-by-step explanation:

Null Hypotheses,

$H_0 : p=0.8\\H_a: p>0.80$

So we use z-test for one population proportion (right-tailed test)

According to this informaton, we defined that

$\alpha=0.05$

$z_c=1.64$ (critical value)

So our Rejection region is $R={z:z>1.64}$

$z=\frac{\bar{p}-p_0}{\sqrt{p_0(1-p_0)/n}} = \frac{0.755-0.8}{\sqrt{0.8(1-0.8)/200}}=-1.591$

Not rejection.

6 0

3 years ago

A vehicle travels 57 kilometers north and then travels 26 kilometers south. What is the current position of the vehicle? (2 poin

solniwko [45]

Answer:

C. 31 kilometers north of its starting location

Step-by-step explanation:

<em>Please see attached a rough sketch of the situation for your reference</em>.

Step one:

Displacement North= 57km

Displacement South= 26km

Required

The final displacement

The current position is attained by subtracting 26km from 57km

=57-26= 31km

Therefore the current position is

C. 31 kilometers north of its starting location

5 0

3 years ago