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nydimaria [60]
2 years ago
5

If you answer this your littearly a pro hacker pls help ​

Mathematics
2 answers:
gladu [14]2 years ago
6 0

Answer:

6 times 3 times 4

18 times 4

= 72

Step-by-step explanation:

hope this helps good luck

mafiozo [28]2 years ago
6 0

Answer:

See below!:

Step-by-step explanation:

What we can do is use the formula to find volume: l * w * h

If we use this, by counting, we can see that the length is 6 units. Adding onto that, we can also see that the width is 3 units. Finally, for the height, we can see that it is 4 units.

If we use our handy formula, we get 6×3×4 which gives us 72 units!

You might be interested in
What is the point of intercection of lines y=x and y=2x+1
12345 [234]

Answer:

(-1, -1)

Step-by-step explanation:

Let's set these two equations equal to each other to solve the system:

x = 2x + 1

Solving for x, we get x = -1

Plug this value of x back into any of the two equations to get y: y = 2 * (-1) + 1 = -1.

Thus, the point of intersection is (-1, -1).

Hope this helps!

8 0
3 years ago
Read 2 more answers
3x+y=4<br> 2x+y=5<br> solve using linear combination
Advocard [28]
Idk what linear combination is but you can solve this way:
3x+y=4
-2x-y=-5
x=-1
3(-1)+y=4
-3+y=4
y=7
So x=-1 and y=7
3 0
3 years ago
Read 2 more answers
Paul has 16 fish pictures and 12 deer pictures. He wants to arrange the pictures in rows with the same numbers of fish and of de
VladimirAG [237]

Answer:

4 rows

Step-by-step explanation:

GCF of 12 and 16 is4

5 0
3 years ago
Two lawn care companies are competing for a landscaping contract. Company A charges a $5 daily consulting fee plus $8 per square
gladu [14]
5 + 8s = 15 + 3s
8s - 3s = 15 - 5
5s = 10
s = 10/5
s = 2 <=== they will charge the same at 2 sq ft
8 0
3 years ago
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

5 0
3 years ago
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