Tyler should make 8 a day. You do 122-66 which is 56 and there are 7 days in a week so 56 divide by 7 is 8.
Answer:
x= 7
Step-by-step explanation:
add (12x+1) and (5x-3) which becomes 17x-2 and then set that equal to 117 and solve. move the 2 to the right side of the equation which becomes 17x=119 and then divide 119 by 17 which x equals 7.
plug in 7 for x to make sure you get 117
Answer:
x=2
Step-by-step explanation:
Original width = 6
New width 6+x+x
Orignal length 12
New length 12+x+x
A = l*w
160 = ( 6+2x) ( 12+2x)
Factor
160 = 2( 3+x) 2(6+x)
Divide each side by 4
40 = (3+x) (6+x)
FOIL
40 = 18+ 6x+3x+ x^2
40 = 18 +9x+x^2
Subtract 40 from each side
0 = x^2 +9x -22
Factor
0 = (x +11) (x-2)
Using the zero product property
x +11 =0 x-2 =0
x= -11 x=2
Since we cannot have a negative sidewalk
x =2
Answer:
LCM (7, 18 and 21) = 126
Step-by-step explanation:
Step 1: Address input parameters & values
Intergers: 7 18 21
LCM (7, 18, 21) = ?
Step 2: Arrange the group of numbers in the horizontal form with space or comma separated format
7, 18 and 21
Step 3: Choose the divisor which divides each or most of the integers of in the group (7, 18 and 21), divide each integers separately and write down the quotient in the next line right under the respective integers. Bring down the integer to the next line if the integer is not divisible by the divisor. Repeat the same process until all the integers are brought to 1.
Step 4: Multiply the divisors to find the LCM 7, 18 and 21
7 × 3 × 6 = 21
LCM(7, 18, 21) = 126
The least common multiple for three numbers 7, 18, and 21 is 126
Given:
8 tasks
5/6 hours total
Unit rate per task:
5/6 hours ÷ 8 tasks = 5/6 * 1/8 = 5/48 or 0.10 hours per task
0.10 hours x 60 minutes/hour = 6 minutes per task.
Unit rate per hour:
8 tasks ÷ 5/6 hours = 8 * 6/5 = 48/5 = 9.60 tasks per hour or rounded to 10 tasks per hour.
