2 years ago

What are the domain restrictions of q2−3q−4q2−7q−8?

Mathematics

1 answer:

ioda2 years ago

8 0

Answer:

{xer}

Step-by-step explanation:

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Answer:

Step-by-step explanation:

9/3

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Marysya12 [62]

Answer:

$-2x^{2} -7x-6$

Step-by-step explanation:

(2x + 3) (-x - 2)

distribute first term, to the second term:

2x(-x) + 2x(-2) + 3(-x) + 3(-2)

multiply:

$(-2x^{2})$ + (-4x) + (-3x) + (-6)

$-2x^{2} -4x-3x-6$

combine the like terms:

$-2x^{2}$ - 4x - 3x - 6

-7x

$-2x^{2}$ - 7x - 6

final answer :

$-2x^{2}$ - 7x - 6

hope this helped !!

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valentinak56 [21]

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Anon25 [30]

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This is because 6x + (-6x) = 6x - 6x = 0

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Anybody Knows The Answer?

Nastasia [14]

Answer:

Proportional

Step-by-step explanation:

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