WILL GIVE BRAINLIEST + 5 STAR x= Length= Width=

22) John ordered a large pizza for $19.50. How much

siniylev [52]

i believe its $21.84 because 12% would be $2.34

Step-by-step explanation:

7 0

3 years ago

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An urn contains ten chips. An unknown number of chips are white' the others are red. We wish to test:

Olin [163]

Answer:

Let’s denote X to be the number of white chips in the sample and E be the event that exactly half of the chips are white. Then,

a) Find α

α = P (reject H0 | H0 is true) = P (X ≥ 2|E)

= P (X = 2|E) + P (X = 3|E),

We took two case, as we can draw only only three chips with two or more white to reject H0, it means we can only take 2 white chips or 3, not more, we get solution

= (5C2 * 5C1)/10C3 + (5C3 * 5C0)/10C3

= 0.5

So, α = 0.5

b) Find β

i) Let E1 be the event that the urn contains 6 white and 4 red chips. (As given)

β = P (accept H0 | E1) = P (X ≤ 1|E1)

= (6C0 * 4C3)/10C3 + (6C1 * 4C2)/10C3

= 1/3

= 0.333

So, β = 0.333

i) Let E2 be the event that the urn contains 7 white and 3 red chips. (As given)

β = P (accept H0 | E2) = P (X ≤ 1|E2)

= (7C0 * 3C3)/10C3 + (7C1 * 3C2)/10C3

= 11/60

= 0.183

So, β = 0.183

5 0

4 years ago

What is an equation in point-slope form for the line that passes through the points (-1, 4) and (3, -4)

Crank

Here you go I hope this helps!! :)

8 0

3 years ago

Is there a transformation that maps shape I onto shape ll?

OLEGan [10]

Is there a picture to see from ?

6 0

3 years ago

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Question 9

Angelina_Jolie [31]

The first car consumed 40 gallons of gas and second car consumed 30 gallons of gas

Solution:

Let x = gallons consumed by car 1

Let y = gallons consumed by car 2

Fuel efficiency of car 1 = 15 miles per gallon

Distance covered in 1 gallon of gas = 15 miles

Fuel efficiency of car 2 = 25 miles per gallon

Distance covered in 1 gallon of gas = 25 miles

Given a total gas consumption of 70 gallons

Therefore,

gallons consumed by car 1 + gallons consumed by car 2 = 70

x + y = 70 ------ eqn 1

The two cars went a combined total of 1350 miles

Therefore,

gallons consumed by car 1 x distance covered in 1 gallon of gas of car 1 + gallons consumed by car 2 x distance covered in 1 gallon of gas of car 2 = 1350

$x \times 15 + y \times 25 = 1350$

15x + 25y = 1350 ----- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

x = 70 - y ------- eqn 3

Substitute eqn 3 in eqn 2

15(70 - y) + 25y = 1350

1050 - 15y + 25y = 1350

10y = 1350 - 1050

10y = 300

y = 30

Substitute y = 30 in eqn 3

x = 70 - 30

x = 40

Thus first car consumed 40 gallons of gas and second car consumed 30 gallons of gas

4 0

4 years ago