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Tresset [83]
3 years ago
14

Timed please hurry

Physics
2 answers:
Natasha_Volkova [10]3 years ago
7 0

☆゚.*・。゚Hello ☆゚.*・。゚

♡━━━━━━━━━━━━━━━━━━━━━━━━♡

TanakaBro is here to hel^{p}:

✷━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━✷

The answer to this is:

True:

✯ EXPLANATION:

Because Dissociative identity disorder, do wandering away from home from they depression, they parents always fighting, having bad grades in school. having a different change about you. Having about they anger, and about they mentally emotionally.

Hope It Helped!

And tell me if The answer is wrong. . .

Good Luck With Your Assignment!

#LearnWithBrainly

Answer:

- TanakaBro

Kobotan [32]3 years ago
4 0
The answer would be true.
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Insulation or insulating. :) Hope that helps!
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Problem 3: A basketball player is running at 4.75 m/s toward the basket when he jumps into the air to dunk the ball. He maintain
LekaFEV [45]

Answer

given,

speed of the basketball player, v_x = 4.75 m/s

height of the jump = ?

a) initial vertical velocity = 0 m/s

   final vertical velocity = ?

       height, h = 0.75 m

 using equation of motion

   v² = u² +  2 g h

   v² = 0² +  2 x 9.8 x  0.75

   v² = 14.7

   v = 3.83 m/s

b) let horizontal distance= x m

 maximum height at time , t s

 time taken to reach maximum height

    t = \dfrac{3.83}{9.8}

         t = 0.39 s

    horizontal distance

             = v_x  × t

             = 4.75 × 0.39

             = 1.85 m

horizontal distance is equal to 1.85 m

8 0
3 years ago
When moving a couch, you exert a force of 400N and push it 4.0m. How much work have you done on the couch?
Aleks04 [339]

Answer:

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7 0
3 years ago
The electric potential inside a charged spherical conductor of radius R is is given by V = keQ/R, and the potential outside is g
Bumek [7]

Answer:

For outer points of shell

E = \frac{k_eQ}{r^2}

Now for inner point of shell

E = 0

Explanation:

As we know that out side the shell electric potential is given as

V = \frac{K_e Q}{r}

inside the shell the electric potential is given as

V = \frac{K_e Q}{R}

now we know the relation between electric potential and electric field as

E = - \frac{dV}{dr}

so we can say for outer points of the shell

E = -\frac{dV}{dr}

E = - \frac{d}{dr}(\frac{K_eQ}{r})

E = \frac{k_eQ}{r^2}

Now for inner point again we can use the same

E = - \frac{dV}{dr}

E = - \frac{d}{dr}(\frac{K_eQ}{R})

E = 0

6 0
3 years ago
Suppose that the Sun were to collapse from its current radius of about 700,000 km to a radius of only about 6000 km (about the r
Maksim231197 [3]

Answer:

Only there will be a change in density of sun.

Explanation:

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8 0
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