Answer:
Explanation:
F = ma
4.45g - 2.75g = (4.45 + 2.75)a
a = 9.81(4.45 - 2.75) / (4.45 + 2.75) = 2.31625 ≈ 2.32 m/s²
a)
T = 2.75(9.81 + 2.32) = 33.3 N
or
T = 4.45(9.81 - 2.32) = 33.3 N
b) 2.32 m/s² upward for 2.75 kg mass
2.32 m/s² downward for 4.45 kg mass
c) y = ½at² = ½(2.31625/3)1² = 1.158125 ≈ 1.16 m
The equilibrium temperature of aluminium and water is 33.2°C
We know that specific heat of aluminium is 0.9 J/gm-K, and that of water is 1 J/gm-K
Now we can calculate the equilibrium temperature
(mc∆T)_aluminium=(mc∆T)_water
15.7*0.9*(53.2-T)=32.5*1*(T-24.5)
T=33.2°C
1. Velocity
2. Time
3. Idk
4. Idk
5. D. I think it may be A. but I think D.
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