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Thepotemich [5.8K]
2 years ago
13

What’s Is Example Of

Physics
1 answer:
ahrayia [7]2 years ago
3 0

*heat transfer energy, As it always flow from higher temperature to lower temperature till it reach the thermal equilibrium.

example: -friction.

- collisions.

- the hot cup which's hotter than your hand✋will transfer heat in your hand. and a cold piece of ice which's colder than your hand to causing the heat transfer out of your hand .

*temperature ️ depends on the move of particle and we have a different shape of motion like:

translational motion.

rotational motion.

vibrational motion.

when the temperature:

increases it has more kinetic energy and faster moving particles and the object expanded which known as (thermal expansion).

decreases it has less kinetic energy and slower moving particles.

As kinetic energy is 1/2 mV².

example: -the mercury in thermometers.

*Absolute zero :

The theoretical temperature at which substances possess no thermal energy, equal to 0 K, −273.15°C, or −459.67°F.

*specific heat "c" :

is essentially a measure of how thermally insensitive a substance is to the addition of energy.

c=Q/m∆T

where Q is energy .

note water has a higher specific heat, and lower temperature.

*conduction <em><u>example</u></em> When the stove is turned on, the skillet becomes very hot due to the conduction of heat from the burner to the skillet.

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Explique ¿por que un objeto que tiene energía es capaz de realizar un trabajo?
Nana76 [90]
By striking another object that is free to move, the moving object can exert a force and cause the second object to shift its position. While the object is moving, it has the capacity for doing work. Energy means the ability to do work, so all moving things have energy by virtue of their motion.




Translation: Al golpear otro objeto que se puede mover libremente, el objeto en movimiento puede ejercer una fuerza y ​​hacer que el segundo objeto cambie de posición. Mientras el objeto se mueve, tiene la capacidad de realizar un trabajo. Energía significa la capacidad de realizar un trabajo, por lo que todas las cosas en movimiento tienen energía en virtud de su movimiento.

3 0
2 years ago
HELP
Free_Kalibri [48]

Answer:

Explanation:

Although there is absolutely NO regard for significant digits, I can help you with this, nonetheless.

The equation for Potential Energy is PE = mgh. We have everything but the height of the ball. We have to solve for that using a one-dimensional motion equation:

v² = v₀² + 2aΔx, where Δx is our displacement (the height we need for PE). Filling in and keeping in mind that at the max height of parabolic travel, the final velocity of the object is 0:

0 = (21.5)² + 2(-9.8)Δx and

0 = 462.25 - 19.6Δx and

-462.25 = -19.6Δx so

Δx = 23.58 m. Using this as the h in our PE equation:

PE = .19(9.8)(23.58) so

PE = 43.9 J, choice C.

8 0
3 years ago
Please dont ask people to be "Bf" and "gf" On this app. This is for school. So all of you please be safe!! Thank you.
Ksju [112]
People do that on here?
4 0
3 years ago
Read 2 more answers
A 3000-N force gives an object an acceleration of 15 m/s2. The mass of the object is
7nadin3 [17]
<h3>Answer:</h3>

200 kg

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Physics</u>

<u>Newton's Law of Motions </u>

Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion

Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)

Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u> </u>

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] F = 3000 N

[Given] a = 15 m/s²

[Solve] m = <em>x</em> kg

<u>Step 2: Solve for </u><em><u>m</u></em>

  1. Substitute in variables [Newton's Second Law of Motion]:                          3000 N = m(15 m/s²)
  2. [Mass] [Division Property of Equality] Isolate <em>m</em> [Cancel out units]:            200 kg = m
  3. [Mass] Rewrite:                                                                                               m = 200 kg
5 0
2 years ago
refrigerant 134a enters a compressor operating at steady state as saturated vapor at 0.12 MPa and exits at 1.2 MPa and 70 C at a
Afina-wow [57]

Answer:

the power input to the compressor is 7.19Kw

Explanation:

Hello!

To solve this problem follow the steps below.

1. We will call 1 the refrigerant state at the compressor inlet and 2 at the outlet.

2. We use thermodynamic tables to determine enthalpies in states 1 and 2.

(note: Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties such as pressure and temperature.  )

h1[quality=1, P=0.12Mpa)=237KJ/Kg

h2(P=1.2Mpa, t=70C)=300.6KJ/kg

3. uses the first law of thermodynamics in the compressor that states that the energy that enters a system is the same that must come out

Q=heat=0.32kJ/s

W=power input to the compressor

m=mass flow=0.108kg/S

m(h1)+W=Q+m(h2)

solving for W

W=Q+m(h2-h1)

W=0.32+0.108(300.6-237)=7.19Kw

the power input to the compressor is 7.19Kw

7 0
3 years ago
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