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Thepotemich [5.8K]
2 years ago
13

What’s Is Example Of

Physics
1 answer:
ahrayia [7]2 years ago
3 0

*heat transfer energy, As it always flow from higher temperature to lower temperature till it reach the thermal equilibrium.

example: -friction.

- collisions.

- the hot cup which's hotter than your hand✋will transfer heat in your hand. and a cold piece of ice which's colder than your hand to causing the heat transfer out of your hand .

*temperature ️ depends on the move of particle and we have a different shape of motion like:

translational motion.

rotational motion.

vibrational motion.

when the temperature:

increases it has more kinetic energy and faster moving particles and the object expanded which known as (thermal expansion).

decreases it has less kinetic energy and slower moving particles.

As kinetic energy is 1/2 mV².

example: -the mercury in thermometers.

*Absolute zero :

The theoretical temperature at which substances possess no thermal energy, equal to 0 K, −273.15°C, or −459.67°F.

*specific heat "c" :

is essentially a measure of how thermally insensitive a substance is to the addition of energy.

c=Q/m∆T

where Q is energy .

note water has a higher specific heat, and lower temperature.

*conduction <em><u>example</u></em> When the stove is turned on, the skillet becomes very hot due to the conduction of heat from the burner to the skillet.

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This is because of the conservation of angular momentum, which allows most planets to spin in the same direction, but Venus and Uranus have seem to ignore this as they spin in different directions, as Venus spins clockwise and Uranus is on its side
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3 years ago
A star produces 2x10^26 watts. how much energy does it lose every minutes
Step2247 [10]

Answer:

Energy loss per minute will be 120\times 10^{26}j

Explanation:

We have given the star produces power of 2\times 10^{26}W

We know that 1 W = 1 J/sec

So 2\times 10^{26}W=2\times 10^{26}J/sec

Given time = 1 minute = 60 sec

So the energy loss per minute =2\times 10^{26}\times 60=120\times 10^{26}j

We multiply with 60 we have to calculate energy loss per minute

7 0
3 years ago
Water is boiled at sea level in a coffeemaker equipped with an immersion-type electric heating element. The coffee maker contain
Luden [163]

Answer:

P=1362\ W

t'=251.659\ s is time required to heat to boiling point form initial temperature.

Explanation:

Given:

initial temperature of water, T_i=18^{\circ}C

time taken to vapourize half a liter of water, t=18\ min=1080\ s

desity of water, \rho=1\ kg.L^{-1}

So, the givne mass of water, m=1\ kg

enthalpy of vaporization of water, h_{fg}=2256.4\times 10^{-3}\ J.kg^{-1}

specific heat of water, c=4180\ J.kg^{-1}.K^{-1}

Amount of heat required to raise the temperature of given water mass to 100°C:

Q_s=m.c.\Delta T

Q_s=1\times 4180\times (100-18)

Q_s=342760\ J

Now the amount of heat required to vaporize 0.5 kg of water:

Q_v=m'\times h_{fg}

where:

m'=0.5\ kg= mass of water vaporized due to boiling

Q_v=0.5\times 2256.4

Q_v=1.1282\times 10^{6}\ J

Now the power rating of the boiler:

P=\frac{Q_s+Q_v}{t}

P=\frac{342760+1128200}{1080}

P=1362\ W

Now the time required to heat to boiling point form initial temperature:

t'=\frac{Q_s}{P}

t'=\frac{342760}{1362}

t'=251.659\ s

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3 years ago
Why isnt geothermal energy used more often​
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Risk of return on investment is higher than other forms of energy generation.
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Do you even juul bro?
blsea [12.9K]

Answer:

No

Explanation:

5 0
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