Basically, you want to take the integral of each interval and compare them. The two intervals with the same integral represent equal displacement of the particle. And since delta(x) is always 2, all you have to do is average the initial and final velocities of each interval and multiply by two to find total displacement.
Hope it helped.
Edit to show calculations:
2 * [ (0 + 10)/2 ] = 10 for interval AB
2 * [ (7 + 3)/2 ] = 10 for interval DE
I think the answer to this is chemical
Answer:
See the answers below.
Explanation:
We can solve both problems using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F =m*a
where:
F = force [N] (units of newtons)
m = mass = 1000 [kg]
a = acceleration = 3 [m/s²]
![F = 1000*3\\F=3000[N]](https://tex.z-dn.net/?f=F%20%3D%201000%2A3%5C%5CF%3D3000%5BN%5D)
And the weight of any body can be calculated by means of the mass product by gravitational acceleration.
![W=m*g\\W=1000*9.81\\W=9810 [N]](https://tex.z-dn.net/?f=W%3Dm%2Ag%5C%5CW%3D1000%2A9.81%5C%5CW%3D9810%20%5BN%5D)