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Naddik [55]
3 years ago
12

Can someone help me with this chem question?

Chemistry
2 answers:
pickupchik [31]3 years ago
7 0

Answer:

Malleable

Explanation:

IceJOKER [234]3 years ago
7 0
Answer:

C - Good thermal insulator

Explanation:

Metals are ductile, malleable, and are good electrical conductors. They are also good conductors of heat, but that doesn’t mean they make good thermal insulators.
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If the percentage ionization of an 0.10 M acid is 3.0%, what is its pH
Alchen [17]

2.52 answer=c. That is the pH.


6 0
3 years ago
What is the solubility in moles/liter for silver chloride at 25 oC given a Ksp value of 1.6 x 10-10. Write using scientific nota
trapecia [35]

Answer:

Explanation:

AgCl      ⇄       Ag⁺       +       Cl⁻

m                       m                   m

If x mole of AgCl be dissolved in one litre .

[ Ag⁺ ] [ Cl⁻ ] = 1.6 x 10⁻¹⁰

m² =  1.6 x 10⁻¹⁰

m = 1.26 x 10⁻⁵ moles

So solubility of AgCl is 1.26 x 10⁻⁵ moles / L

5 0
3 years ago
(03.05 LC)
Ainat [17]

Answer:

The correct answer is 4

Explanation:

Boron trifluoride (BF₃) has a molecular geometry (as shown in the image in the question) referred to as trigonal planar; this is because each of the the fluorine atoms/molecules (bonded to the central boron atom) is placed in such a way that they form the three "end points"/"domains" of an equilateral triangle. Hence, the correct option is the last option.

7 0
3 years ago
What is the ph of a 0.014 M HCL solution?
Allushta [10]

Answer:

pH = 1.853

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

[H_3O^+] = [HCl] = 0.014

pH  = -log [H^+] = -log [H_3O^+]

Substituting the available values in above equation, we can say that   the pH of the solution is equal to

- log (0.014)

pH = 1.853

pH of a 0.014 M HCL solution = 1.853

8 0
3 years ago
he heat of fusion of tetrahydrofuran is . Calculate the change in entropy when of tetrahydrofuran melts at . Be sure your answer
lana [24]

Answer:

\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Explanation:

Hello.

In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

\Delta S=\frac{n*\Delta H}{T}

Whereas n accounts for the moles which are computed below:

n=5.9g*\frac{1mol}{72g} =0.082mol

Thus, the entropy turns out:

\Delta S=\frac{0.0819mol*8.5 kJ/mol}{(-108.5+273.15)K}\\\\\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Best regards.

3 0
3 years ago
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