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3 years ago

Same price, d.

Mathematics

1 answer:

allsm [11]3 years ago

8 0

Answer: ddddd

Step-by-step explanation:

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30 points!!!!!

dlinn [17]

HELLO...!!

Diagonal = ?
Wide = 20 in.
High = 15 in.

Pythagoras formula: D² = H² + W²

$D^2=(15)^2+(20)^2\\ \\D^2=225+400\\ \\D^2=625\\ \\D= \sqrt{625}\\ \\D=25\ in.\quad\Longrightarrow\boxed{\boxed{\mathbb{ANSWER\ \checkmark}}}\\ \\ \\\textbf{HOPE\ THIS\ HELPS...!!}$

6 0

3 years ago

3 to the fifth power over 3

ycow [4]

Answer:

Step-by-step explanation:

$\frac{3^5}{3}$ = $3^{4}$ or 81.

5 0

3 years ago

Read 2 more answers

Help!! I need to answer this question.

babunello [35]

"AC/DF = 5/2" is correct.

8 0

3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

4 years ago

The probability that a student uses Smarthinking Online Tutoring on a regular basis is 0.31 . In a group of 21 students, what is

Ivenika [448]

Answer: 0.0241

Step-by-step explanation:

This is solved using the probability distribution formula for random variables where the combination formula for selection is used to determine the probability of these random variables occurring. This formula is denoted by:

P(X=r) = nCr × p^r × q^n-r

Where:

n = number of sampled variable which in this case = 21

r = variable outcome being determined which in this case = 5

p = probability of success of the variable which in this case = 0.31

q= 1- p = 1 - 0.31 = 0.69

P(X=5) = 21C5 × 0.31^5 × 0.69^16

P(X=5) = 0.0241

4 0

4 years ago