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Sedaia [141]
3 years ago
13

X2 = 14 − 3x is my question​

Mathematics
1 answer:
vladimir1956 [14]3 years ago
5 0
X=14/5 if you want solution here:
Use the commutative property to reorder the terms: 2x=14-3x
Move the variable to the left - hand side and change sign: 2x+3x=14
Collect like terms: 5x=14
Divide both sides of the equation by 5: x=14/5
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MUSTONENTS
VMariaS [17]

Answer:

15 quarters

Step-by-step explanation:

15 quarters = $3.75

21 dimes = $2.10

15 + 21 = 36 coins

3.75 + 2.10 = 5.85

4 0
3 years ago
Find the values of x and y - i will give brainliest if right
kherson [118]

Answer:

itd x=68 and y=5 I apolgize if its wrong

4 0
3 years ago
154 and 145 to the nearest hundred
Yuki888 [10]

Answer: 154: 200 145: 100

Step-by-step explanation:

If the number next to the place value is 5 or more you round it up. Like I did 154. But if the number is less that 5 you put everything to zero EXCEPT for the place value you are rounding. Good Luck

5 0
3 years ago
Read 2 more answers
A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running
Alborosie

Answer:

x_1 =2 , x_2=7

Step-by-step explanation:

Consider the revenue function given by R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

\frac{dR}{dx_1} = -10x_1-2x_2+34 =0

\frac{dR}{dx_2} = -16x_2-2x_1+116 =0

From the first equation, we get, x_2 = \frac{-10x_1+34}{2}.If we replace that in the second equation, we get

-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156

From where we get that x_1 = \frac{156}{78}=2. If we replace that in the first equation, we get

x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7

So, the critical point is (x_1,x_2) = (2,7). We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives  and check if the criteria is fulfilled in order for it to be a maximum. We get that

\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}

\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16

We have the following matrix,  

\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right].

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is (-10)\cdot (-16) - (-2)(-2) = 156>0 and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0
3 years ago
Read 2 more answers
Solve for b .<br><br> + b = -1<br> b =
Alik [6]

Answer:

b = -1

Step-by-step explanation:

Solve for b means, write in the form of b =...

Given

+ b = - 1 and this is the same as b = - 1.

That is because the plus sign has no real meaning here, so you can ignore it as if it was not there at all.

It so turns out you now have the answer!

7 0
3 years ago
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