Question

Use the square roots property to solve the quadratic equation (y+150)2=50.

Answer 1

We can take the square root of both sides, adding a plus/minus sign of the right hand side:

$\sqrt{(y+150)^2}=\pm\sqrt{50}\iff y+150 = \pm\sqrt{50}$

Then, we subtract 150 from both sides:

$y=\pm\sqrt{50}-150$

So, the two solutions are

$y_1 = \sqrt{50}-150,\quad y_2 = -\sqrt{50}-150$