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igomit [66]
2 years ago
11

A certain company sells tea in loose leaf and bagged form, and in five flavors: Darjeeling, earl grey, chamomile, peppermint, an

d orange pekoe. The company packages the tea in boxes that contain either 8 ounces of tea of the same flavor and the same form, or 8 ounces of tea of 4 different flavors and the same form. If the order in which the flavors are packed does not matter, how many different types of packages are possible
Mathematics
1 answer:
ANTONII [103]2 years ago
7 0

Answer:

- 20

Step-by-step explanation:

Given that,

Flavors of tea = 5

Types of packaging = 2

So,

No. of possibilities = 5 * 2

= 10

A.T.Q.,

4 from 5 total flavors will be included in the variety pack, the number of available choices = 5C4

= 5 choices

Since 5 choices are probable for each form, The total in two forms would be 5 * 2 = 10.

Therefore,

Total no. of different packs can be possible = 10 + 10

= 20

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Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC
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Answer:

DC=\frac{8}{3}\ units

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

BM^2=AB^2-AM^2

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AB=5\ units\\AM=x\ units

substitute

BM^2=5^2-x^2

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<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

BM^2=BC^2-MC^2

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substitute

BM^2=7^2-(9-x)^2

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BM^2=49-81+18x-x^2

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substitute the given values

DC=9-2(\frac{19}{6})

DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units

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3 years ago
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