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sveta [45]
2 years ago
10

SAT verbal scores are normally distributed with a mean of 430 and a standard deviation of 120 (based on data from the College Bo

ard ATP). (a) If a single student is randomly selected, find the probability that the sample mean is above 500. (b) If a sample of 35 students are selected randomly, find the probability that the sample mean is above 500. These two problems appear to be very similar. Which problem requires the application of the central limit theorem, and in what way does the solution process differ between the two problems?
Mathematics
1 answer:
Sav [38]2 years ago
6 0

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a:

a) 0.281 = 28.1% probability that the sample mean is above 500.

b) 0.0003 = 0.03% probability that the sample mean is above 500.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 430, hence \mu = 430.
  • The standard deviation is of 120, hence \sigma = 120.

Item a:

The probability is the <u>p-value of Z when X = 500</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 430}{120}

Z = 0.58

Z = 0.58 has a p-value of 0.719.

1 - 0.719 = 0.281

0.281 = 28.1% probability that the sample mean is above 500.

Item b:

Sample of 35, hence n = 35, s = \frac{120}{\sqrt{35}}

Then:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{500 - 430}{\frac{120}{\sqrt{35}}}

Z = 3.45

Z = 3.45 has a p-value of 0.9997.

1 - 0.9997 = 0.0003

0.0003 = 0.03% probability that the sample mean is above 500.

To learn more about the <u>normal distribution and the central limit theorem</u>, you can take a look at brainly.com/question/24663213

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170.35 cm² are needed to make the can of soda (not in the choices)

Step-by-step explanation:

The surface area of a cylinder = 2πrh + πr², where

  • r is the radius of its base
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  • π is about 3.14

∵ The soda can is made from aluminum

∵ The can is shaped a cylinder with radius 3.5 cm

∴ r = 3.5

∵ Its height is 6 cm

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- The aluminium that needed to make the can is the surface area

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∵ The surface area of the can = 2πrh + πr²

- Substitute r by 3.5, h by 6 and π by 3.14

∴ The surface area of the can = 2(3.14)(3.5)(6) + (3.14)(3.5)²

∴ The surface area of the can = 131.88 + 38.465

∴ The surface area of the can = 170.345 cm²

- Round it to the hundredths' place

∴ The aluminium are needed = 170.35 cm²

170.35 cm² are needed to make the can of soda

Learn more:

You can learn more about the surface area in brainly.com/question/12041380

#LearnwithBrainly

7 0
3 years ago
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A 222-inch pipe is cut into two pieces. One piece is five times the length of the other. Find the length of the shorter piece.
viktelen [127]

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The shorter piece is <u>37</u> inches long.

Step-by-step explanation:

Let the length of the shorter piece be x and the longer piece be 5x.

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It was reported that about 80% of airline tickets-nearly $65 billion worth last year are issued over the internet. What were the
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Answer:

The answer is nearly $81 billion.

Step-by-step explanation:

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