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stira [4]
3 years ago
15

Question 1 (1 point)

Physics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

The magnitude of the boy's displacement is 24.698 paces which is in the direction of approximately 58.24° North of East

Explanation:

The given parameters are;

The distance West the boy on a treasure hunt walks = 12 paces

The distance North the boy on a treasure hunt then walks = 21 paces

The distance East the boy on a treasure hunt then walks = 25 paces

Writing the displacement in vector format, gives;

d = -12·i + 21·j + 25·i

Which gives

d = 13·i + 21·j

The magnitude of the boy's resultant displacement is given as follows;

\left | \mathbf{d} \right | = \sqrt{d_x^2 + d_y^2}

Where;

d_x = 13, \ d_y = 21

\left | \mathbf{d} \right | = \sqrt{13^2 + 21^2} = \sqrt{610}  \approx 24.698 \ paces

The magnitude of the boy's displacement is 24.698 paces

The direction of the displacement is tan⁻¹(21/13) ≈ 58.24° North of East.

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Which involves more work in the scientific sense: moving the boxes and the furniture down from the second floor or up to the fif
Advocard [28]

Answer:

moving the boxes and the furniture up to the fifth floor.

Explanation:

The work done when moving an object up or down is equal to its change of gravitational potential energy:

W=mg \Delta h

where

m is the mass of the object

g is the gravitational acceleration

\Delta h is the change in height of the object

We have two opposite situations:

1) when an object is moved upward, \Delta h is positive, so the work done W is positive as well: this means that we need to do work in order to move the object, because we have to "win" the effect of gravity, which pulls the object downward

2) when an object is moved downward, \Delta h is negative, so the work done W is negative as well: this means that we do not need to do work on the object, because it is already done by gravity, which pulls the object downward.

Therefore, more work is done when we are moving the boxes and the furniture up to the fifth floor.

8 0
3 years ago
Batman and Robin are attempting to escape that dastardly villain, the Joker, by hiding in a large pool of water (refractive inde
dusya [7]

Answer:

 x_total = 4.29m

 

Explanation:

To solve this exercise we must work in parts. Let's use the law of refraction to find the angle of the refracted ray and trigonometry to find the distances.

Let's start by looking for the angles that the laser refracts

        n₁ sin θ₁ = n₂ sin θ₂

where n₁ is the air refraction compensation n₁ = 1, n₂ the water refractive index n₂ = 1,333

        θ₂ = sin⁻¹ (n₁  sin θ₁/n₂)

        θ₂ = sin⁻¹ (1 sin 27 / 1,333)

        θ₂ = sin⁻¹ 0.34057

        θ₂ = 19.9º

now let's find the distance from the edge of the pool to the point where the ₂lightning strikes the water

               tan θ₁ = y₁ / x₁

               x₁ = y₁ / tan θ₁

               x₁ = 1.49 / tan 27

               x₁ = 2,924 m

Now let's look for the waterfall in the water as far as Robin

             tan θ₂₂ = y₂ / x₂

               

             x₂ = y₂ / tan θ₂

             x₂ = 3.77 / tan 19.9

             x₂ = 1,364

the distance from the edge of the pool to Robin is

              x_total = x₁ + x₂

              x_total = 2,924 + 1,364

              x_total = 4.29m

 

7 0
4 years ago
Why do people hate on people and hate country people. are you country
Dmitry_Shevchenko [17]

Answer:

why do people hate on people and hate country people. are you country

because they only think about. themselves and they also think that they are always right .

it's my point of view

hope it is helpful to you

3 0
3 years ago
Read 2 more answers
A 25.0 kg bumper car moving to the right at 5.00 m/s overtakes and col-
kramer

Explanation:

This problem bothers elastic collision.

Given data

Mass m1= 25kg

Initial velocity u1= 5m/s

Final velocity v1= 1.5m/s

Mass m2= 35kg

Initial velocity u2=?

Final velocity v2 = 4.5m/s

A. To find the initial velocity of the 35kg car, let us Apply the principle of conservation of energy

m1u1+m2u2= m1v1+m2v2

25*5+ 35*u2= 25*1.5+ 35*4.5

125+35u2= 37.5+157.5

125+35u2=195

35u2= 195-125

35u2= 70

u2= 2m/s

The initial velocity is 2m/s

B. Totally not kinetic energy before impact

KE= 1/2m1u1²+ 1/2m2u2²

KE= (25*5²)/2+ (35*2²)/2

KE= 625/2 +140/2

KE= 312.5+70

KE= 382.5J

Total kinetic energy after impact

KE=1/2m1v1²+ 1/2m2v2²

KE= (25*1.5²)/2 +(35*4.5²)/2

KE= 56.25/2 +708.75/2

KE=28.125 +354.375

KE= 382.5J

We can see that energy is conserved

Kinetic energy before and after impact remains unchanged

8 0
4 years ago
If an automobile engine delivers a power of 50.0 hp, how much time will it take for the engine to do 6.40 x 10^5 j of work? (1 h
Troyanec [42]

Answer:

17.2 s

Explanation:

Power = Energy / Time

50(746) = 6.40×10^5 / Time

Time = <u>17.2s</u>

6 0
3 years ago
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