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Vanyuwa [196]
3 years ago
4

Chem question!! With reference to the "Chemistry at Work" box on explosives, use bond enthalpies to estimate the enthalpy change

for the explosion of 1.00 g of nitroglycerin.
I found that the answer is 7.85 KJ, but how?
Chemistry
1 answer:
Jlenok [28]3 years ago
3 0

The mass of nitroglycerin is 1 g,

Molar mass of nitroglycerin is 227 g/mol

The number of moles = moles/molar mass

= 1 g / 227 g/mol

= 0.004405 mol

The equation for the bond enthalpy of the reaction is shown below, thus, the total enthalpy change in the reaction is as follows:

ΔHreaction = Number of moles (∑ΔHbond break - ∑ΔH bond forms)

= 0.004405 mol × -3564.5 kJ/mol

= -7.85 kJ

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Answer: no

Explanation:

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You are planning to prepare 600 mL of 20% dextrose solution, by mixing your 5% and 50% dextrose solution. How much of each solut
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3 years ago
A person of 82 kg is in an elevator. If the elevator is moving at a speed of 5m/s, what’s the person’s kinetic energy.
andre [41]

Answer:

The person’s kinetic energy is 1,025 J

Explanation:

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and in a position of rest, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its state of rest by applying a force.

Kinetic energy is represented by the following formula:

Ec=\frac{1}{2}*m*v^{2}

where Ec is kinetic energy, which is measured in Joules (J), m is mass measured in kilograms (kg), and v is velocity measured in meters over seconds (m/s).

In this case:

  • Ec= ?
  • m= 82 kg
  • v= 5 \frac{m}{s}

Replacing:

Ec=\frac{1}{2}*82 kg*(5\frac{m}{s} )^{2}

Solving:

Ec= 1,025 J

<u><em>The person’s kinetic energy is 1,025 J</em></u>

3 0
3 years ago
What is 0.000005670 written in proper scientific notation?
viva [34]
5.67.................
4 0
3 years ago
Calculate the mass of Octane needed to release 6.20 mol Co2
n200080 [17]
The combustion reaction of octane is as follow,

                           C₈H₁₈  +  25/2 O₂     →     8 CO₂  +  9 H₂O

According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
                                     X  =  (114.23 g × 6.20 mol) ÷ 8 mol

                                     X  =  88.52 g of Octane
Result:
           88.52 g of Octane is needed to release 6.20 mol CO₂.
8 0
3 years ago
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