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iragen [17]
3 years ago
12

Light ray 1 strikes the smooth surface, separating air and water as shown below. A horizontal line is drawn and the part above t

he line is labeled Air and the part below the line is labeled Water. There is one slanting ray labeled 1 which falls on the line at a point and there are four rays of light labeled 2, 3, 4, and 5 which move away from same point on the line. Ray 5 is exactly vertical to the line and below the line, ray 4 is on the right of ray 5 and makes an angle of about 25 degrees with ray 5. Ray 3 is above the line and makes an angle of about 25 degrees with the line. Ray 2 is on the right of ray 1 and ray 1 and ray 2 make angles of about 25 degrees with the vertical at the point where ray 1 strikes. Which of the following rays is the part of ray 1 that is reflected from the smooth surface? Ray 2 Ray 3 Ray 4 Ray 5
Chemistry
2 answers:
FinnZ [79.3K]3 years ago
8 0

I think the correct answer is ray 2.

Vera_Pavlovna [14]3 years ago
8 0

Answer:

it is ray two

Explanation:

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The following reaction was performed in a sealed vessel at 791 ∘C : H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at
OlgaM077 [116]

Answer:

4.31 × 10²

Explanation:

Equation of the reaction;

H_{2(g)} + I_{2(g)}     ⇌     2HI_{(g)

The ICE Table is shown as follows:

                            H_{2(g)}         +         I_{2(g)}        ⇌     2HI_{(g)

Initial                    3.10                     2.50                  0      

Change                 - x                       -x                     + 2x      

Equilibrium        (3.10 - x)                0.0800              2x

From I_{2(g)}   ;

We can see that 2.50 - x = 0.0800

So; we can solve for x;

x = 2.50 - 0.0800

x = 2.42

H_{2(g)}  which = (3.10 -x) will be :

= 3.10 - 2.42

= 0.68

2HI_{(g) = 2x

= 2 (2.42)

= 4.84

K_c = \frac{[HI]^2}{[H_2][I_2]}

K_c = \frac{(4.84)^2}{(0.68)(0.0800)}

K_c =\frac{23.4256}{0.0544}

K_c = 430.62

K_c ≅ 431

K_c = 4.31 × 10²

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Explanation:

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