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marishachu [46]

3 years ago

7

Someone pls help me ill give out brainliest pls don’t answer if you don’t know

1 answer:

Vikki [24]3 years ago

4 0

Median is average. So add together all 18 tuition costs (4 times 2999 from dark blue, 6 times 5999 for green, 3 8999 for turquoise, and 11999 for red. Then add those all together. After that divide by 18(number of schools included in graph, also where we pulled that information from) that is how yoh find the median, or average.

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. Which equation translates y = |x| by 8 units to the left?

stepladder [879]

|x+8|
Moves it 8 units to the left

4 0

3 years ago

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Denise Rose the number cube that has sides labeled 1 to 6 and then flips a coin what is the probability that she rolls in odd nu

NARA [144]

1.36 percent chance hand ks

4 0

3 years ago

Y-int for 2n^2+5n-25=0

luda_lava [24]

The intercept is -25 because for a quadratic equation in the form
$ax {}^{2} + bx + c$
the c value or the number without a variable attached is the y intercept

5 0

3 years ago

A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

5 0

3 years ago

Which of the following is equivalent to 2 ln e^ln 5x = 2 ln 15?

neonofarm [45]

Answer:

x = 3

Step-by-step explanation:

Given in the question an equation,

$2lne^{ln5x}=2ln15$

Step 1

$e^{lnx}=x$

so,

$2ln(5x)=2ln15$

Step 2

cancel 2 on both sides of the equation

$ln{5x}=ln15$

Step 3

$ln{5x}-ln15=0$

$ln\frac{5x}{15}=0$

Step 4

$ln\frac{x}{3}=0$

Step 5

$e^{ln\frac{x}{3}}=e^{0}$

Step 6

x/3 = 1

x = 3(1)

x = 3

8 0

3 years ago