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AURORKA [14]
3 years ago
6

A falling ball of mass 0.5 kg experiences a downward force due to gravity of mg (where g = 9.8 m/s2) and an upward force of air

resistance equal to 3.5 N. What is the ball's acceleration in units of m/s2? Record your answer.
Physics
1 answer:
schepotkina [342]3 years ago
6 0

Applying Newton's Second Law of Motion, the acceleration of the ball is 16.8 m/s^2

<u>Given the following data:</u>

  • Mass = 0.5 kg
  • Acceleration due to gravity = 9.8 m/s^2
  • Upward force = 3.5 N.

To find ball's acceleration, we would apply Newton's Second Law of Motion:

First of all, we would determine the net force acting on the ball.

Net \; force = Upward\;force + Downward\;force

Downward\;force = 0.5 × 9.8

Downward force =  4.9 N

Net \; force = 3.5 + 4.9

Net force = 8.4 N

Mathematically, Newton's Second Law of Motion is given by this formula;

Acceleration = \frac{Net\;force}{Mass}\\\\Acceleration = \frac{8.4}{0.5}

<em>Acceleration = 16.8 </em>m/s^2<em />

Therefore, the acceleration of the ball is 16.8 m/s^2

Read more here: brainly.com/question/24029674

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Answer:

Object 2 has the larger drag coefficient

Explanation:

The drag force, D, is given by the equation:

D = 0.5 c \rho A v^2

Object 1 has twice the diameter of object 2.

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d_1 = 2d

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A_1 = \frac{\pi (2d)^2 }{4}\\A_1 = \pi d^2

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D = 0.5 c_1 \rho A_1 v^2\\D = 0.5 c_1 \rho (\pi d^2) v^2

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