The answer is potential for this question
Answer:
Explanation:
5 C = 278 K
25 C = 298 K
V1 / T1 = V2 / T2
1.5L / 278 K = V2 / 298 K
V2 = (1.5L * 298) / 278
V2 = 1.61 L
Answer:
I = (5.71 i ^ + 6.99j ^) N s
Explanation:
The concept of impulse is very useful for problems where shocks occur, the impulse is equal to the change of moment of the system
I = Δp = m -m v₀
Let's fix an xy coordinate system, where y is vertical and we decompose the velocities
Initial
sin (-40) = / vo
cos (-40) = v₀ₓ / Vo
= 17.0 sin (-40)
= -10.93 m / s
Vox = 17 cos (-40)
Vox = 13.02 m / s
Final
sin 30 = / vf
cos 30 = / Vf
= 48.0 sin30
= 24.0 m / s
= 48 cos 30
= 41.57 m / s
Let's calculate the momentum on each axis
X axis
Iₓ = m -m
Iₓ = 0.200 (41.57 - 13.02)
Iₓ = 5.71 N s
Axis y
= m - m
= 0.2000 (24 - (-10.93))
= 6.99 N s
I = (5.71 i ^ + 6.99j ^) n s
The speed of a transverse wave( v) = 117.03 m/s
The formula we can use in this case would be:
v = sqrt (T / (m / l))
Where,
v = is the velocity of the transverse wave = unknown (?)
T = is the tension on the rope = 380 N
m = is the mass of the rope = 86.0 g = 0.086 kg
l = is the length of the rope = 3.1 m
Substituting the given values into the equation to search for the speed v:
v = sqrt (380 N/(0.086 kg /3.1 m))
v = sqrt (380 * 3.1/ 0.086)
v = sqrt (13,697.67)
v = 117.03 m/s
speed of a transverse wave( v) = 117.03 m/s
Learn more about transverse wave here:
brainly.com/question/23165088
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