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Alecsey [184]
1 year ago
6

Suppose a fireworks shell explodes, breaking into three large pieces for which air resistance is negligible. How is the motion o

f the center of mass affected by the explosion
Physics
1 answer:
denis-greek [22]1 year ago
3 0

The center of mass isn't affected by the explosion.

To find the answer, we need to know about the trajectory of motion at zero external force.

<h3>How is the trajectory of an object changed when the net external force on it is zero?</h3>
  • When there's no net external force acting on an object, its momentum doesn't change with time.
  • As its momentum doesn't change, so it continues with the original trajectory.
<h3>Why doesn't the trajectory of firework change when it's exploded?</h3>
  • When a firework is exploded, its internal forces are changed, but there's no external force.
  • So, although the fragments follow different trajectories, but the trajectory of center of mass remains unchanged.

Thus, we can conclude that the center of mass isn't affected by the explosion.

Learn more about the trajectory of exploded firework here:

brainly.com/question/17151547

#SPJ4

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Answer:

x ’= 368.61 m,  y ’= 258.11 m

Explanation:

To solve this problem we must find the projections of the point on the new vectors of the rotated system  θ = 35º

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we calculate

            x ’= 450 cos 35

            x ’= 368.61 m

            y ’= 450 sin 35

            y ’= 258.11 m

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