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Alecsey [184]
2 years ago
6

Suppose a fireworks shell explodes, breaking into three large pieces for which air resistance is negligible. How is the motion o

f the center of mass affected by the explosion
Physics
1 answer:
denis-greek [22]2 years ago
3 0

The center of mass isn't affected by the explosion.

To find the answer, we need to know about the trajectory of motion at zero external force.

<h3>How is the trajectory of an object changed when the net external force on it is zero?</h3>
  • When there's no net external force acting on an object, its momentum doesn't change with time.
  • As its momentum doesn't change, so it continues with the original trajectory.
<h3>Why doesn't the trajectory of firework change when it's exploded?</h3>
  • When a firework is exploded, its internal forces are changed, but there's no external force.
  • So, although the fragments follow different trajectories, but the trajectory of center of mass remains unchanged.

Thus, we can conclude that the center of mass isn't affected by the explosion.

Learn more about the trajectory of exploded firework here:

brainly.com/question/17151547

#SPJ4

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A long uniformly charged thread (linear charge density λ= 2.5 C/m) lies along the x axis in the figure.(Figure 1) A small charge
Kamila [148]

Answer 1) The electric field at distance r from the thread is radial and has magnitude  

E = λ / (2 π ε° r)  

The electric field from the point charge usually is observed to follow coulomb's law:  

E = Q / (4  π ε° r^{2})  

Now, adding the two field vectors:  

E_{thread}  =  {2.5 / (22 π ε° X 0.07 ) ; 0}  

Answer 2) E_{q}  = {2.3 / (4 2 π ε°) ( - 7/ (√(84); -12 / (√84))

Adding these two vectors will give the length which is magnitude of the combined field.  

The y-component / x-component gives the tangent of the angle with the positive x-axes.

Please refer the graph and the attachment for better understanding.

5 0
3 years ago
Which of the following changes would decrease the coefficient of friction needed for this ride?
posledela
Friction occurs between two contacting surfaces. The coefficient of friction is very much dependent on the roughness of these surfaces. Some of the many ways in which the coefficient can be lessened or decreased are to lubricate the surface or make it shiny by eliminating the spikes which caused the roughness. 
7 0
3 years ago
Help with either I don’t understand this I know W=f*d but don’t get how it applies here
rosijanka [135]

Answer:

5) Displacement = +3.125 m

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6) Force = -53.89 N

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Explanation:

5) We are given;

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Workdone; W = +500 J

Now, formula for workdone is;

W = Force × displacement

Thus, displacement = Work/force

Displacement = 500/160

Displacement = +3.125 m

Thus, displacement is in the same direction as the force vector.

6) We are given;

Displacement; d = 18 m.

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Like in the first answer above,

Workdone = Force × Displacement

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Force = Workdone/Displacement

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Since force is negative and displacement is positive, it means force is in an opposite direction relative to the displacement.

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Answer:

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