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Sorry if this is not what you want me to do and I just threw a bunch of words at you.
The force of friction on the box is 8.82 N.
The force of friction is given by the formula
F=μN
Here N is the normal force of the box=mg=3*9.8=29.4 N
Now the static friction force on the box is=0.4*29.4=11.76 N
Since the box is applied with the horizontal pull of 15 N, which is greater than the static friction, therefore the box must be in the moving condition, in that case there is dynamic friction force is applied on the box=0.3*29.4=8.8 N
Therefore the force of friction on the box is 8.8 N.
-Brody was exposed to harmful noise
-Ashley’s ears have aged
-Keaton has bacteria in his ear
-Brian has earwax build up
The correct answer is gamma
Gamma rays are the most penetrating ones and as much as a meter of concrete is needed to stop them, so a few centimeters is nothing.
Answer:
y (t) = 0.754 * cos ( 7.96 t - 69.52)
Explanation:
Given:
m = 1.5 kg , k = 95 N / m , v₀ = 6 m / s , d = 0.35 m , t = 0
y (t) = A * cos ( ω * t - φ )
Using the equation that describe the motion
m * v = - k * x ⇒ m * x'' = - k * x
Angular velocity is equal to
ω = √ k / m ⇒ ω = √ 95 N /m / 1.5 kg
ω = 7.96 rad /s
A = v / ω ⇒ A = 6 m /s / 7.96 rad / s
A = 0.754
d = cos * φ ⇒ φ = cos ⁻¹ * 0.35
φ = 69.52
y (t) = A * cos ( ω * t - φ ) ⇒ y (t) = 0.754 * cos ( 7.96 t - 69.52)
