The magnitude of the electric field at the dot is : 10⁴ v/m
<h3>What is electric field?</h3>
Electric field is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.
Given that there are three equipotential lines with equal spacing,we will apply the the relationship between P.D and electric field
Determine the magnitude of the electric field at the dot
change in voltage = E .d

From equation ( 1 )
The magnitude of electric field will be given as


Hence we can conclude that The magnitude of the electric field at the dot is : 10⁴ v/m
Learn more about electric field :
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Answer:
The maximum velocity the mass can have if the string is not to break = 29.05 m/s
Explanation:
The force balance in the mass:
The tension in the string must always be equal to the force keeping the mass in horizontal circular motion.
The force keeping the mass in circular motion is given by
F = mv²/r
m = mass of body = 0.4 kg
v = speed of the body in circular motion
r = radius of the circular motion = 0.75 m
Maximum tension the string can withstand will correspond to the maximum velocity of the body in horizontal circular motion
T = F = mv²/r
450 = (0.4)(v²)/(0.75)
v² = 450×0.75/0.4 = 843.75
v = 29.05 m/s
Answer:
Explanation:
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Infertile Land.
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Answer:
R = 5.28 103 km
Explanation:
The definition of density is
ρ = m / V
V = m /ρ
Where m is the mass and V the volume of the body
The volume of a sphere is
V = 4/3 π r³
Let's replace
4/3 π r³ = m / ρ
R =∛ ¾ m / ρ π
The mass of the planet is
M = 5.5 Me
R = ∛ ¾ 5.5 Me /ρ π
Let's reduce the density to SI units
ρ = 1.76 g / cm³ (1 kg / 10³ g) (10² cm / 1 m)³
ρ = 1.76 10³ kg / m³
Let's calculate
R = ∛ ¾ 5.5 5.97 10²⁴ / (1.76 10³ pi)
R = ∛ 0.14723 10²¹
R = 0.528 10⁷ m
R = 0.528 104 km
R = 5.28 103 km
Answer:


Explanation:
<u>Displacement
</u>
It's a vector magnitude that measures the space traveled by a particle between an initial and a final position. The total displacement can be obtained by adding the vectors of each individual displacement. In the case of two displacements:

Given a vector as its polar coordinates (r,\theta), the corresponding rectangular coordinates are computed with


And the vector is expressed as

The monkey first makes a displacement given by (0.198 km,0°). The angle is 0 because it goes to the East, the zero-reference for angles. Thus the first displacement is

The second move is (145 m , -15.8°). The angle is negative because it points South of East. The second displacement is

The total displacement is


In (magnitude,angle) form:



