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slamgirl [31]
3 years ago
5

in which level of organization would the roots of a plant most likely be classified? Please explain too

Chemistry
1 answer:
abruzzese [7]3 years ago
8 0

Kaka ml nyu yan wala kaming paki kung ano ang lagi ginagawa nyu

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A student has a balloon that looks shiny like a metal and wants to perform an experiment to determine if it contains any metal.
zheka24 [161]

Answer:

Charge the balloon, hold it near an electroscope, and determine if the electroscope leaves move.

Explanation:

The gold leaf electroscope is an instrument used to detect if a body is charged. It has two gold leafs suspended from a brass stem in a vacuumed glass jar and connected to a metal cap(Toppr).

When the test body is allowed to touch the metal cap, a change in the size of the leaves shows whether the body is charged or not.

Since we are suspecting the balloon to be made up of a metal; metals can be charged. We can test if there is really a charge on the balloon by bringing it near an electroscope to see if the electroscope moves.

3 0
3 years ago
PLEASE HELP ME!!!! ILL FIND A WAY TO GET YOU 100 POINTS!!!
Umnica [9.8K]

It’s c had this problem last week

8 0
3 years ago
Convert 27.7 kilometers to centimeters.
Stolb23 [73]

Answer:

The correct answer is - 2770000 cm.

Explanation:

1 kilometer = 1000 meter

1 meter = 100 centimeter

1 kilometer = 100*1000 cm

1 km = 100000 cm.

then,

27.7 kilometers = 2.77 × 10^6 centimeters

So, 27.7 kilometers = 27.7 × 100000

= 2.77 × 106 or 2770000 centimeters.

7 0
2 years ago
A 2 L container contains 5 moles of helium gas at 0.5 atm. What is the<br> temperature of the gas?
lara [203]

Answer:

2.44 K IS THE TEMPERATURE OF THE GAS

Explanation:

PV = nRT

P = 0.5 atm

V = 2 L

n = 5 moles

R = 0.082 L atm mol^-1 K^-1

T = ?

Substituting for T in the equation, we obtain:

T = P V / nR

T = 0.5 * 2 / 5 * 0.082

T = 1 / 0.41

T = 2.44 K

The temperature of the gas is 2.44 K

7 0
3 years ago
After an electric sign is turned on, the temperature of its glass goes from 23.5°C to 65.5°C. The sign’s glass has a mass of 905
julia-pushkina [17]

The sign's glass absorbed 25466.7 J

<h3>Further explanation</h3>

Given

The temperature of glass :  23.5 °C to 65.5 °C

mass = 905 g

the specific heat capacity = 0.67 J/g °C

Required

Heat absorbed

Solution

Heat absorbed by sign's glass can be formulated :

\tt Q=m.c.\Delta T

ΔT=65.5 - 23.5 = 42

\tt Q=905\times 0.67\times 42\\\\Q=\boxed{\bold{25466.7~J}}

5 0
3 years ago
Read 2 more answers
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