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3 years ago

in which level of organization would the roots of a plant most likely be classified? Please explain too

Chemistry

1 answer:

abruzzese [7]3 years ago

8 0

Kaka ml nyu yan wala kaming paki kung ano ang lagi ginagawa nyu

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What is carbon in the lithosphere initially a part of before part of the burning of fossil fuel?

dedylja [7]

Carbon in the lithosphere is held in soil in the form of both organic and inorganic carbon which often as calcium carbonate. Carbon can leave the soil through soil respiration – which releases CO2, or by erosion – which can carry it into rivers or the ocean, where it then enters the hydrosphere.

7 0

3 years ago

Read 2 more answers

given a density of 350 grams/cm3 and a mass of 25 grams. What is the volume using the equation involving density?

Eduardwww [97]

0.07cm³

Explanation:

Given parameters:

Density of the body = 350g/cm³

Mass of the body = 25g

Unknown:

Volume of the body = ?

Solution:

Density is the amount of substance contained in a volume of body. It is expressed as:

Density = $\frac{mass}{volume}$

Since the unknown is volume, we make it the subject of the expression;

Volume = $\frac{mass}{density}$

Volume = $\frac{25}{350}$ = 0.07cm³

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

6 0

3 years ago

What is the volume of an 2.3 solution with 212 grams of calcium chloride dissolved in it

Travka [436]

830 mL. A 2.3 mol/L solution of CaCl2 has a volume of 830 mL

I am guessing that the concentration of your solution is 2.3 mol/L.

a) Moles of CaCl2

MM of CaCl2 = 110.98 g/mol

Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)

= 1.910 mol CaCl2

b) Volume of solution

V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution

= 830 mL solution

5 0

3 years ago

9. Write the number in place value table of 820245<br>

Burka [1]

Answer:

8----hundred thousands

2----ten thousands

0----thousands

2----hundreds

4----tens

5---ones

place value

8 = 800,000

2 = 20,000

0 = 0,000

2 = 200

4 =40

5 =5

5 0

3 years ago

100.0 mL of Ca(OH)2 solution is titrated with 5.00 x 10–2 M HBr. It requires 36.5 mL of the acid solution for neutralization. Wh

miskamm [114]

Answer:

The number of moles HBr = 0.001825

The concentration of Ca(OH)2 = 0.009125 M

Explanation:

Step 1: Data given

Volume of the Ca(OH)2 = 100.0 mL = 0.100 L

Molarity of HBr = 5.00 * 10^-2 M

Volume of HBR = 36.5 mL = 0.0365 L

Step 2: The balanced equation

Ca(OH)2 + 2HBr → CaBr2 + 2H2O

Step 3: Calculate molarity of Ca(OH) 2

b*Va* Ca = a * Vb*Cb

⇒with b = the coefficient of HBr = 2

⇒with Va = the volume of Ca(OH)2 = 0.100 L

⇒with ca = the concentration of Ca(OH)2 = TO BE DETERMINED

⇒with a = the coefficient of Ca(OH)2 = 1

⇒with Vb = the volume of HBr = 0.0365 L

⇒with Cb = the concentration of HBr = 5.00 * 10^-2 = 0.05 M

2 * 0.100 * Ca = 1 * 0.0365 * 0.05

Ca = (0.0365*0.05) / 0.200

Ca = 0.009125 M

Step 4: Calculate moles HBr

Moles HBr = concentration HBr * volume HBr

Moles HBr = 0.05 M * 0.0365 L

Moles HBr = 0.001825 moles

3 0

3 years ago