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Kay [80]
3 years ago
12

Ca(hco3)2 molecular formula calculated​

Chemistry
1 answer:
GrogVix [38]3 years ago
7 0

Answer:

C2H2CaO6

Explanation:

Ca same

H × 2

C × 2

O3 × 2

I hope this helps you :)

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The following charges on individual oil droplets were obtained during an experiment similar to Millikan's. Determine a charge fo
RSB [31]

Answer:

- 1.602 x 10⁻¹⁹coulombs

Explanation:

Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.

LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹)  because it is  already a common factor to all.

The LCM  is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.

4 0
3 years ago
Calculate the number of moles present in 9.50g of co2
pshichka [43]

Answer:

0.4318 mol

Explanation:

Moles= mass/ mollar mass

Moles= 9.50/22

Moles= 0.4318 mol

3 0
4 years ago
The central core of an atom is called the __?
PilotLPTM [1.2K]

Answer: Atomic Nucleus!

Explanation: All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons, which have a positive electrical charge, and neutrons, which have no charge.

(Yes, it was from google.)

6 0
3 years ago
Describe the relationship between temperature and particle movement
soldi70 [24.7K]

Answer:

If matter is heated and thus its temperature rises more and more, it can be seen that the particles contained in it move ever faster – be it the relatively free movement of the particles in gases or the oscillation around a rest position in solids. The temperature of a substance can therefore be regarded as a measure of the velocity of the particles it contains. With a higher temperature and thus higher particle

Explanation:

7 0
3 years ago
Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0
3 years ago
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