Ca(hco3)2 molecular formula calculated

a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calc

ladessa [460]

Answer:

The molarity of the solution is 1.1 $\frac{moles}{liter}$

Explanation:

Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

$molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case

number of moles of solute= 0.564 moles
volume= 0.510 L

Replacing:

$molarity=\frac{0.564 moles}{0.510 L}$

Solving:

molarity= 1.1 $\frac{moles}{liter}$

The molarity of the solution is 1.1 $\frac{moles}{liter}$

4 0

2 years ago

in rutherford's gold foil experiment a very small number of alpha particles were deflected. what about the structure of the atom

zvonat [6]

Answer:The atom being mostly empty space. A small number of alpha particles were deflected by large angles (> 4°) as they passed through the foil. There is a concentration of positive charge in the atom. Like charges repel, so the positive alpha particles were being repelled by positive charge

8 0

2 years ago

Which of the following possess the greatest concentration of hydroxide ions?

jek_recluse [69]

Answer : The correct option is (d) a solution of 0.10 M NaOH

Explanation :

(a) a solution of pH 3.0

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-3.0=11$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$11=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-11}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-11}M$

(b) a solution of 0.10 M $NH_3$

As we know that 1 mole of $NH_3$ is a weak base. So, in a solution it will not dissociates completely.

So, the $OH^-$ concentration will be less than 0.10 M

(c) a solution with a pOH of 12.

We have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$12=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-12}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-12}M$

(d) a solution of 0.10 M NaOH

As we know that $NaOH$ is a strong base. So, it dissociates to give $Na^+$ ion and $OH^-$ ion.

So, 0.10 M of $NaOH$ in a solution dissociates to give 0.10 M of $Na^+$ ion and 0.10 M of $OH^-$ ion.

Thus, the $OH^-$ concentration is, 0.10 M

(e) a $1\times 10^{-4}M$ solution of $HNO_2$

As we know that 1 mole of $HNO_2$ in a solution dissociates to give 1 mole of $H^+$ ion and 1 mole of $NO_2^-$ ion.

So, $1\times 10^{-4}M$ of $HNO_2$ in a solution dissociates to give $1\times 10^{-4}M$ of $H^+$ ion and $1\times 10^{-4}M$ of $NO_2^-$ ion.

The concentration of $H^+$ ion is $1\times 10^{-4}M$

First we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (1.0\times 10^{-4})$

$pH=4$

Now we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-4=10$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$10=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-10}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-10}M$

From this we conclude that, a solution of 0.10 M NaOH possess the greatest concentration of hydroxide ions.

Hence, the correct option is (d)

3 0

3 years ago

Animals inherit traits from their parents. They pass some of these same traits on to their children. Suppose a pair of animals h

Fantom [35]

Answer:

A. The children will be more likely to survive than if they did not have the trait.

Explanation:

Process of elimination

B. It will not affect the children.

Cannot be true, if it didn't impact the children then how would survival of the fittest work?

D. The children will be able to adapt if the environment changes.

That just... not how adapting works when it comes to evolution.

C. The children will be more likely to survive than their parents were

Everyone has the same trait, everyone is equal in that regard.

A. The children will be more likely to survive than if they did not have the trait.

"Suppose a pair of animals has a trait that helps them survive in their environment." The trait helps them survive. Not having the trait makes them less likely to survive. A is correct

8 0

2 years ago

Select the correct answer. What is the percent composition of silicon in silicon carbide (SiC)? A. 28% B. 50% C. 70% D. 142%

Nadya [2.5K]

Answer:

C. 70%

Explanation:

Atomic Mass of the silicon = 28 g.

Atomic mass of the Carbon = 12 g.

Total mass of the Silicon Carbide = 28 + 12

= 40 g.

Now, Using the formula.

% Composition = Mass of the silicon/Total mass of the compound × 100 %

= 28/40 × 100 %

= 70 %

Hence, % composition of the silicon in SiC is 70%

7 0

2 years ago

Ca(hco3)2 molecular formula calculated​

Ca(hco3)2 molecular formula calculated