Answer:
76.0%
Explanation:
Let's consider the following reaction.
CaCO₃(s) ⇄ CaO(s) + CO₂(g)
At equilibrium, the equilibrium constant Kp is:
Kp = 1.16 = pCO₂ ⇒ pCO₂ = 1.16 atm
We can calculate the moles of CO₂ at equilibrium using the ideal gas equation.
From the balanced equation, we know that 1 mole of CO₂ is produced by 1 mole of CaCO₃. Taking into account that the molar mass of CaCO₃ is 100.09 g/mol, the mass of CaCO₃ that reacted is:
The percentage by mass of the CaCO₃ that reacted to reach equilibrium is:
in digital signals, codes are used while in analogue signals do not use signals.
<h3>What are signals?</h3>
Signals are defined as the instructions which are transferred to another source in other to deliver a message.
There are two types of signals which include the digital and analogue signals.
The digital signals uses codes which is a secret way of sending messages while analogue doesn't use codes.
Learn more about codes here:
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If the patient has to take 2 tablets every 8 hours for 7 days.
24/8=3 3*2=6
this means that he patient will have to take 6 tablets every day.
6*7=42 And the patient must take 42 tablets in all 7 days
Hope this helps! :)
Answer:
The correct answer is it adds a UMP molecule to glucose-1-phosphate by splitting out pyrophosphate.
Explanation:
UDP glucose pyrophosphorylase enzyme also known as UTP-glucose-1-phsphate uridylyltransferase.
This enzyme plays an important role during synthesis of glycogen also known as glycogenesis.
During the reaction the enzyme UDP glucose pyrophosphorylase transfer uridine monophosphate to glucose-1-phosphate resulting in the formation of UDP glucose along with the release of pyrophosphate moiety.
Glucose-1-phosphate+UTP⇆UDP-glucose+ppi
