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3 years ago

14

Find the Ka of nitrous acid given that a 0.20 M solution of the acid has a hydrogen ion concentration of 2.8*10-3 M. HNO2 (aq) ?

H+ (aq) + NO2- (aq)

1 answer:

Otrada [13]3 years ago

4 0

Answer:

3.92 x 10⁻⁵.

Explanation:

∵ [H⁺] = √(Ka.c)

∴ Ka = [H⁺]²/c = (2.8 x 10⁻³)²/(0.20) = 3.92 x 10⁻⁵.

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In cats,short hair is dominant to long hair. If a heterozygous short-haired cat is crossed with a homozygous long haired cat,wha

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3 years ago

Write a balanced chemical equation based on the following description:

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<u>the balanced chemical equation was shown here :</u>

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A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) <---> N2(g) 3H2(g) At equilibrium, it was fou

Softa [21]

Answer:

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Explanation:

Equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction and the concentrations of reactants and products are held constant.

Being:

aA + bB ⇔ cC + dD

the equilibrium constant Kc is defined as:

$Kc=\frac{[C]^{c}*[D]^{d} }{[A]^{a} *[B]^{b} }$

In other words, the constant Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients. Kc is constant for a given temperature, that is to say that as the reaction temperature varies, its value varies.

In this case, being:

2 NH₃(g) ⇔ N₂(g) + 3 H₂(g)

the equilibrium constant Kc is:

$Kc=\frac{[N_{2} ]*[H_{2} ]^{3} }{[NH_{3} ]^{2} }$

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and replacing:

$Kc=\frac{0.0551*0.0183^{3} }{0.383^{2} }$

you get:

Kc= 2.30*10⁻⁶

<u><em>Kc for this equilibrium is 2.30*10⁻⁶</em></u>

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4 years ago