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sasho [114]
3 years ago
5

Which of the functions below have period 2pi? Check all that apply. A. y = tan x B. y = sec x C. y = cot x D. y = csc x

Mathematics
2 answers:
swat323 years ago
8 0
The correct answers are y=sec x, and y=csc x
Colt1911 [192]3 years ago
4 0

Answer:

Option B and D are correct that is y=secx and  y=cscx  respectively.

Step-by-step explanation:

We have been given four functions:

CaseA:

y=tanx

\text{Period oftanx is} \pi

Hence, A is correct.

CaseB:

y=secx

\text{Period of secx is} 2\pi

Hence, B is correct.

CaseC:

y=cotx

\text{Period of cotx is} \pi

Hence, C is not correct.

CaseD:

y=cscx

\text{Period of cscx is} 2\pi

Hence, D is correct.

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A video game store allows customers to rent games for 4.75 each. Customers can also buy a membership for $54 annually, and video
ankoles [38]
Answer:

24 video games

Step-by-step explanation:

Let x represent number of video games.
We have been given that a video game store allows customers to rent games for $4.75 each. So the cost of renting x video games would be 4.75x.

We are also told that customers can also buys a membership for $54 annually, and video games would only cost $2.50 each. The cost of renting x video games after membership would be 2.50x + 54

To find the number of video-games that will cost same for both options, we will equate both expressions as:

4.75x = 2.50x + 54
4.75x - 2.50x = 2.50x - 2.50x + 54


Therefore, a customer would have rent 24 video games in a year in order for the two options to be equal.
3 0
2 years ago
Models with a finite calling population
vazorg [7]

Answer:

C. Use the size of the population as a parameter in the operating characteristics formulas.

Step-by-step explanation:

Models with a finite calling population use the size of the population as a parameter in the operating characteristics formulas.

4 0
3 years ago
1( m² + 15m + 56) = (____) (m+8)<br>2 a² +5ab + 6b²=(a +2b (_____)<br><br>pastor po ​
Nutka1998 [239]

Step-by-step explanation:

1.

{m}^{2}  + 15m + 56 = ( \:  \:  \:  \:  \: )(m + 8) \\ solution \\  \:  \: taking \: lhs \\   = {m}^{2}  + 15m + 5 \\   = {m}^{2}  + (7 + 8)m + 56 \\ \:  \:  \: \:    = {m}^{2}  + 8m + 7m + 56 \:  \:  \\ now \: taking \: common \: factor \\  m(m + 8) + 7(m + 8) \\ (m + 7)(m + 8) \\ now \\  {m}^{2}  + 15m + 56 = (m + 7)(m + 8)

2.

{a}^{2}  + 5ab +  6 {b}^{2} = ( a + 2b)( \:  \:  \:  \:  \:  \:  \:  \: ) \\ solution \\ taking \:  \: lhs \\  =  {a}^{2}  + 5ab + 6 {b}^{2} \\ =  {a}^{2}  + ( 3+ 2)ab + 6 {b}^{2} \\  =  {a}^{2}  + 3ab + 2ab + 6 {b}^{2}  \\now \: taking \: common \: factor \\ a(a + 3b) + 2b(a + 3) \\ (a + 2b)(a + 3) \\ now \\ {a}^{2}  + 5ab +  6 {b}^{2} = ( a + 2b)( a + 3) ans

this may help you(:

7 0
2 years ago
Solve the quadratic equation and give both solutions.<br><br> 14x^2 − 29x − 15 = 0
BartSMP [9]

Answer:

Step-by-step explanation:

x_{1,\:2}=\frac{-\left(-29\right)\pm \sqrt{\left(-29\right)^2-4\cdot \:14\left(-15\right)}}{2\cdot \:14}     so    x=\frac{5}{2}     x=-\frac{3}{7}

7 0
3 years ago
What is 67 squared ? give answers
eduard
Here it is
67^2  = 67*67 = 4489 
7 0
3 years ago
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