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bonufazy [111]
2 years ago
14

Here are the dimensions, in cm, of four cuboids.

Mathematics
2 answers:
KatRina [158]2 years ago
5 0

1 x 1 x 5 = 5cm3
5 x 10 x 15 = 750cm3
2 x 3 x 5 = 30 cm3
1 x 2.5 x 4 = 10 cm3

So, the answer is C

professor190 [17]2 years ago
4 0

Answer:

C) 2 × 3 × 5

Step-by-step explanation:

Volume of a cuboid = lbh = 30 cm³

A) 1 × 1 × 5 = 5 cm³ ≠ 30 cm³

B) 5 × 10 × 15 = 750 cm³ ≠ 30 cm³

C) 2 × 3 × 5 = 30 cm³ ✔

D) 1 × 2.5 × 4 = 10 cm³ ≠ 30 cm³

=》The correct option is C) 2 × 3 × 5 as it makes 30 cm³, which is the required volume.

Hope it helps ⚜

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5 0
2 years ago
Evaluate the expression 9 - z9−z9, minus, z when z = 4z=4z, equals, 4
Sophie [7]

Answer:

Step-by-step explanation:

Answer:

<h2>5</h2>

Step-by-step explanation:

Given the expression f(z) = 9-z

To get the value of the resulting value of the function when z = 4, all we need to do is substitute the value of z given into the function to have;

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7 0
3 years ago
What is the distance between (4,2) and (-1,-3)
Sati [7]
<h2>Solving for the Distance between two Points</h2><h3>Answer:</h3>

5 \sqrt{2} or 7.071

<h3>Step-by-step explanation:</h3>

<em>Please refer to my answer from this Question to know more about distances between two points: <u>brainly.com/question/24629826</u></em>

Given:

(4,2)

(-1,-3)

Solving for the Distance:

\sqrt{(4-(-1))^2 +(2 -(-3))^2} \\ \sqrt{(4 +1)^2 +(2 +3)^2} \\ \sqrt{5^2 +5^2} \\ \sqrt{25 +25} \\ \sqrt{50} \\ \sqrt{25 \cdot 2} \\ 5 \sqrt{2}

<u>Note:</u>

5 \sqrt{2} \approx 7.071

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2 years ago
Need help ASAP. Will give brainliest!!!!
julia-pushkina [17]

B1 to H1, B3 to H2, B2 to H3.

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Elena-2011 [213]

<em>Hey </em><em>mate!</em><em>!</em>

<em>Answer:</em>

<em>n(</em><em>A)</em><em>=</em><em>1</em><em>2</em>

<em>Solution</em><em>,</em>

<em>A=</em><em>{</em><em>3</em><em>,</em><em>6</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>1</em><em>,</em><em>2</em><em>4</em><em>,</em><em>2</em><em>7</em><em>,</em><em>3</em><em>0</em><em>,</em><em>3</em><em>3</em><em>,</em><em>3</em><em>6</em><em>}</em>

<em>Just </em><em>count </em><em>the </em><em>elements</em><em>,</em>

<em>There </em><em>are </em><em>1</em><em>2</em><em> </em><em>elements </em><em>in </em><em>the </em><em>set.</em>

<em>So </em><em>the </em><em>cardinal </em><em>number </em><em>of </em><em>the </em><em>set </em><em>is </em><em>1</em><em>2</em><em>.</em>

<h2><em>Hope </em><em>it </em><em>helps.</em><em>.</em><em>.</em></h2>
8 0
2 years ago
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