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algol13
3 years ago
6

The earth’s _____ creates a cross-current motion that captures the north and south moving air creating a ___ _____?

Chemistry
1 answer:
JulsSmile [24]3 years ago
5 0

Answer:

deflection,Coriolis effect

hope this helps

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Write an equation for the reaction of the Tollens reagent<br> withheptanal?
dangina [55]

Answer:

CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 CHO + 2[Ag(NH_3)_2]+  3 H_2 O = CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 COOH +2Ag + 4NH_3

Explanation:

Tollens test is carried out to perceive difference between aldehydes and ketones on the basis of their capability to oxidized easily.

when Tollens react with aldehyde (heptanal) , a silver mirror is form on inner side of container.

The reaction between tollens and heptanal is given as

CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 CHO + 2[Ag(NH_3)_2]+ 3 H_2 O = CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 COOH +2Ag + 4NH_3

8 0
4 years ago
25cm3 of gas at 1 atm has a temperature of 20 degree celsis .
Andreas93 [3]

Answer:

1.28 atm

Explanation:

To solve this problem, you need to use the gas laws, more specifically the Combined Gas Law. It is P1V1/T1 = P2V2/T2. Simply plug your values in. But be careful! Make sure you convert your 20 degree C and 28 deg C to Kelvin, as that it the only temperature scale the Gas Laws work with. Upon plugging in your values, you get approximately 1.28 atm.

6 0
3 years ago
Between energy and life which one comes first answer with scientific reason​
NemiM [27]

Explanation:

While the sun is an excellent source of energy, not all forms of life can utilize the sun's energy directly. This lesson describes how plants transform the sun's energy into potential energy stored in sugar, how living organisms utilize energy in sugar to perform work, and how the relationship between photosynthesis and cellular respiration is necessary for life.

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6 0
3 years ago
Gaseous methane (CH4) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). If 28
elena-14-01-66 [18.8K]

Answer:

68.1% is percent yield of the reaction

Explanation:

The reaction of methane with oxygen is:

CH₄ + 2O₂ → CO₂ + 2H₂O

<em>Where 2 moles of oxygen react per mole of CH₄</em>

<em />

Percent yield is:

Actual yield (28.2g CO₂) / Theoretical yield * 100

To solve this question we need to find theoretical yield finding limiting reactant :

<em>Moles CH₄:</em>

15.1g CH₄ * (1mol / 16.04g) = 0.9414 moles

<em>Moles O₂:</em>

81.2g * (1mol / 32g) = 2.54 moles

For a complete reaction of 0.9414 moles of CH₄ are needed:

0.9414 moles CH₄ * (2 mol O₂ / 1mol CH₄) = 1.88 moles of O₂. As there are 2.54 moles, O₂ is in excess and <em>CH₄ is limiting reactant</em>

In theoretical yield, the moles of methane added = Moles of CO₂ produced. That is 0.9414 moles CO₂. In grams = Theoretical yield:

0.9414 moles CO₂ * (44.01g / mol) = 41.43g CO₂

Percent yield: 28.2g CO₂ / 41.43g CO₂ * 100=

<h3>68.1% is percent yield of the reaction</h3>
6 0
3 years ago
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO 3 ( s ) . The equation for the
Pavlova-9 [17]

Answer:

Mass of O_2 produced = 32 g

Explanation:

Calculation of the moles of KClO_3 as:-

Mass = 82.4 g

Molar mass of KClO_3 = 122.55 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{82.4\ g}{122.55\ g/mol}

Moles= 0.67237\ mol

From the reaction shown below:-

2KClO_3\rightarrow 2KCl+3O_2

2 moles of potassium chlorate on reaction forms 3 moles of oxygen gas

So,

0.67237 moles of potassium chlorate on reaction forms \frac{3}{2}\times  0.67237 moles of oxygen gas

Moles of oxygen gas = 1 mole

Molar mass of oxygen gas  = 32 g/mol

<u>Mass of O_2 produced = 32 g</u>

6 0
4 years ago
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