Mol of HBr = mass/Mr = 117/(1+80) = 1.444
From equation, 2 moles hydrogen bromide reacts with 1 mole of barium hydroxide.... So 1.444 moles of hydrogen bromide react with (1.444/2) = 0.722 moles of barium hydroxide.
When nitric acid is added to water, the concentration of hydronium ions would increase since the nitric acid dissociates into ions, the hydronium ions and the nitrate ions. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
There is 1.6 L of NO produced.
Explanation:
I assume you have an excess of NH3 so that O2 is the limiting reagent.
<u>Step 1:</u> Data given
2.0 liters of oxygen reacts with ammonia
<u>Step 2:</u> The balanced equation
4NH3 + 5O2 → 4NO + 6H2O
For 4 moles of NH3, we need 5 moles of O2 to produce 4 moles of NO and 6 moles of H2O
Consider all gases are kept under the same conditions for pressure and temperature, we can express this mole ratio in terms of the volumes occupied by each gas.
This means: when the reaction consumes 4 liters of ammonia (and 5 liters of oxygen) it produces 4 liters of nitrogen monoxide
Now, when there is 2.0 liters of oxygen consumed, there is 4/2.5 = 1.6 L of nitrogen monoxide produced.
There is 1.6 L of NO produced.
If you have studied enzymes its a similar concept. Cells have proteins on the surface of their cell which hormones bind to (called receptors) The receptor must be a complimentary shape to the hormone for it to bind. Only target cells have the receptor with the complimentary shape so only these cells will be affected.
FeO is Iron II Oxide. You identify that it's an ionic bond so it won't have any prefixes. By reverse criss-crossing the charges, Iron gets a 1+ charge, and Oxygen gets a 1- charge. Since you know that Oxygen has to have a 2- charge, you multiply the 1+ and 1- by 2 to fix their charges, thus giving Iron a 2+ charge and Oxygen a 2- charge.
Since Iron has a 2+ charge, it's roman numeral is II. So the answer is Iron II Oxide.
The other one is Iron III Oxide. By reverse criss-crossing the charges, Fe geta 3+ charge, and Oxygen gets a 2- charge. Since it's correct, the 3+ charge is the roman numeral. So, the answer is Iron III Oxide.
