5^-4 / 5^3
= 5^-1
= 1/5
answer
<span>5^−1
</span><span>1 over 5</span>
I suspect you meant
"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"
• Count the multiples of 10:
⌊100/10⌋ = ⌊10⌋ = 10
• Count the multiples of 7:
⌊100/7⌋ ≈ ⌊14.2857⌋ = 14
• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and
⌊100/70⌋ ≈ ⌊1.42857⌋ = 1
(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)
Then using the inclusion/exclusion principle, there are
10 + 14 - 1 = 23
numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.
Answer:
15 ,90 30 45.90,23,23,45,
0
,12,3,
Step-by-step explanation:
Answer:
You should put "no solution" into the parallel lines box,
you should put "infinite solutions" into the coinciding lines box,
you should put the "(0,0)" and the "(3,-2)" into the intersecting lines box.
Step-by-step explanation:
Answer:
b > -6 or b < 6
Step-by-step explanation:
The absolute value operator always returns a positive number, with |b| = b if b > 0, and |b| = -b if b 0. With this in mind, consider the following inequality:
Because of the absolute value operator, this is valid for b values larger than 6 and less than -6. As a result, the compound inequality that this circumstance illustrates is:
