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GenaCL600 [577]
3 years ago
6

What do electrons Do in ionic bond? Do they transfer from metals to no metals or nonmetal to metals?

Chemistry
1 answer:
9966 [12]3 years ago
6 0

Answer:

electrons get transfered from metals to non metals in the formation of ionic bond.

metals have the tendency to lose electrons whereas non metals tend to stabilize by gaining electrons.

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2 years ago
Why are the transition metals able to show different properties like varying color and paramagnetism ?
Naya [18.7K]

Answer:

Colors of transition metal compounds are due to two types of electronic transitions. Due to the presence of unpaired d electrons, transition metals can form paramagnetic compounds. Transition metals are conductors of electricity, possess high density and high melting and boiling points.

Explanation:

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Hi can u help me pls? I'm totally stuck . The natural source of acidity in rain water is _____.
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Answer-The correct option is option d with says all of the above.

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3 years ago
The boiling point of a substance is tested. After 10 tests, the result is given as 37+/−3°C. Which conclusion can be drawn from
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6 0
1 year ago
Read 2 more answers
g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu
scZoUnD [109]

Answer:

CuCl_2 is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

\frac{1}{2}\times 0.500 mol=0.250 mol of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give  :

\frac{2}{2}\times 0.500 mol=0.500 mol of silver chloride

Mass of silver chloride produced:

0.500 mol × 143.5 g/mol = 71.8 g

7 0
3 years ago
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