When Q is equal the initial concentration of the products / the initial concentration of the reactants.
so, Q = [Ag]*[Cl-] and we neglected [AgCl] as it is solid
∴ Q = 10^-6 * 10^-5
= 10^-11
now we will compare the value of Q with the value of Keq:
when Q = Keq so, the system is in equilibrium
and when Q > Keq so, the reaction will go forward (shift to right) to achieve equilibrium.
and when Q< Keq so, the reaction will go left (shift to left) to achieve equilibrium.
when Q = 10^-11 and Keq = 10^20
∴Q< Keq
and the reaction will shift to left.
Answer:
Becomes 1/4 as much
Explanation:
If a and b are directly proportional, this means we may write an equality between them if some proportionality constant, k, is included, so that:

The equation shows that:

And since k is a constant, this would imply that increasing a by some fraction would also require b to increase by the same fraction.
In the context of this problem, we're given that a becomes 1/4 as much, meaning b should also become 1/4 as much to keep the same proportionality constant, k.
<span>So what happens when there is more than one force? I like to think of net force as if two people were pulling on ropes attached to a big crate. If they pull the crate in the same direction, the crate will accelerate twice as quickly. If they pull in opposite directions with equal forces, the crate won’t move at all — these two forces cancel each other out. If one person pulls northwards and the other pulls eastwards, the crate will move to the north-east.
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Near water, change in elevation, or change in latitude.