Answer:
They could possibly make daily check ups to the research facility?
Answer:
Area of rectangle = 108 cm²
Given:
Base = 6 cm
Height = 18 cm
Explanation:
Area of rectangle = Base × Height
= 6 × 18
= 108 cm²
The density of gold is 19.3 g/cm³
Ag= silver
Au= gold.
density (Ag)=10.5 g/cm³.
density (Au)=19.3 g/cm³
We have to calculate the mass of 5 cm³ silver:
10.5 g---------------------1 cm³
x--------------------------- 5 cm³
x=(10.5 g * 5 cm³) / 1cm³ ≈52.5 g
And we have to calculate the mass of 5 g gold.
19.3 g------------------------1 cm³
x-------------------------------5 cm³
x=(19.3 g * 5 cm³) / 1cm³≈96.5 g
Then 5 cm³ silver are 52.5 g of mass, and 5 cm³ gold are 96.5 g of mass, therefore, gold would have a greater mass than silver.
answer:5 cm³ gold would have a greater mass than 5 cm³ silver.
Answer:
Argon has 8 valence electrons and no extras, it does not require a bond in order to fill its shells, its satisfied by itself.
Chlorine is missing 1 Electron, if it connects with another Chlorine it will be satisfying both of their needs with a Covalent bond.
Explanation:
Answer:
The volume of 0.80 grams of O2 is 0.56 L
Explanation:
Step 1 : Data given
Mass of O2 = 0.80 grams
Molar mass of O2 = 32 g/mol
STP = 1 mol, 1atm, 22.4 L
Step 2: Calculate moles of oxygen
Moles of O2 = Mass of O2 / molar mass of O2
Moles O2 = 0.80 grams / 32 g/mol
Moles O2 = 0.025 moles
Step 3: Calculate volume of O2
1 mol = 22.4 L of gas
0.025 moles = 0.025*22.4L = 0.56 L
The volume of 0.80 grams of O2 is 0.56 L