Answer:
Given : BRDG is a kite that is inscribed in a circle,
With BR = RD and BG = DG
To prove : RG is a diameter
Proof:
Since, RG is the major diagonal of the kite BRDG,
By the property of kite,
∠ RBG = ∠ RDG
Also, BRDG is a cyclic quadrilateral,
Therefore, By the property of cyclic quadrilateral,
∠ RBG + ∠ RDG = 180°
⇒ ∠ RBG + ∠ RBG = 180°
⇒ 2∠ RBG = 180°
⇒ ∠ RBG = 90°
⇒ ∠ RDG = 90°
Since, Angle subtended by a diameter or semicircle on any point of circle is right angle.
⇒ RG is the diameter of the circle.
Hence, proved.
Answer:
A, C, and E
Step-by-step explanation:
-2, 0, and 5
Answer: you will use the cosine rule
Step-by-step explanation:
x^2=11^2+8^2-2(11)(8)xcos(16)
x^2=185-169.18
x^2=15.8
Take square root
x=3.96 or 4
Answer:
The maximum height that the ball will reach is 81 ft
Step-by-step explanation:
Note that the tray of the ball is given by the equation of a parabola of negative main coefficient. Then, the maximum value for a parabola is at its vertex.
For an equation of the form
So
the t coordinate of the vertice is:
In this case the equation is:
So
Therefore
Finally the maximum height that the ball will reach is
Explanation:
Angles 1 & 2 have to equal 180. So, if ∠1 is equal to 140, ∠2 is equal to 40 because 140 + 40 = 180.
So far... we know that:
Angles 2, 9, and 11 make a triangle, a triangles "magic number" is also 180. To get 180, you must add up all of the angles. Well... we don't know ∠11 so to find it, you subtract 40 & 80 from 180. 180 - 80 - 40 = 60.
Answer:
∠2 = 40
∠11 = 60
