Answer: T = 2π√(I/mgD)
Step-by-step explanation:
where:
m is the mass of the pendulum;
I is the moment of inertia of the mass; and
D is the distance from the center of mass to the point of suspension.
Determine the length of the pendulum. For example, it can be equal to 2 m.
Decide a value for the acceleration of gravity. We will use the Earthly figure of 9.80665 m/s², but feel free to check how the pendulum would behave on other planets.
Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s.
Find the frequency as the reciprocal of the period: f = 1/T = 0.352 Hz.
You can also let this simple pendulum calculator perform all calculations for you!
Answer:
11 yd
Step-by-step explanation:
16-5=11 yd
I would use the quadratic formula for this:
x = -b ± √b² - 4ac over 2a
x = 8 ± √64 - 4(1)(0) over 2(1)
x = 8 ± √64 over 2
x = 8 <span>± 8 over 2 [simplify]
x = 4 </span><span>± 4
x1 = 4 + 4 x2 = 4 - 4
x1 = 8 x2 = 0
Thus, the solutions for x would be 0 and 8.</span>
Answer: Ill be glad to help but i need a better picture of the whole thing
Step-by-step explanation:
