The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.
The reaction is:
2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O (1)
The enthalpy of reaction (1) is given by:
(2)
Where:
r: is for reactants
p: is for products
The bonds of the compounds of reaction (1) are:
- 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
- 7O₂: 7 moles of 1 O=O bond
- 4CO₂: 4 moles of 2 C=O bonds
- 6H₂O: 6 moles of 2 H-O bonds
Hence, the enthalpy of reaction (1) is (eq 2):
![\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol](https://tex.z-dn.net/?f=%20%5CDelta%20H%20%3D%20%5B2%2A%286%2A413%20%2B%20347%29%20%2B%207%2A498%20-%20%284%2A2%2A799%20%2B%206%2A2%2A467%29%5D%20kJ%2Fmol%20)
Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.
Read more here:
brainly.com/question/11753370?referrer=searchResults
I hope it helps you!
Methane.
Water - H2O
Methane - CH4
Methane has 2 more hydrogens than water.
Probably Sulfur, low mp and hardness compared to the other metals
Mass of molecule (g) = Mr of substance over avarogado constant
The scientist who studies the earth constituent like solids, gas and liquid is called a geologist. Weathering and erosion are the correct blanks.
<h3>What are weathering and erosion?</h3>
The process of the deterioration of any solid particles like minerals, soils and rocks is called weathering. It occurs due to biochemical substances, atmospheric gases and water pressure.
The process of the transportation of the rocks and mineral particles away from their original position is called erosion it is due to forceful air and water.
The rocks moved from their original place to some another due to weathering and this process of their transportation is called erosion.
Therefore, <u>weathering </u>and <u>erosion </u>are the correct blanks.
Learn more about weathering and erosion here:
brainly.com/question/11712593
