First, we will get the number of moles:
one mole contains Avogadro's number of atoms. Therefore, to know the number of moles in <span>7.83 × 10^24 atoms, we will simply do cross multiplication as follows:
number of moles = (</span><span>7.83 × 10^24*1) / (6.022 * 10^23) = 13 moles
From the periodic table:
mass of one mole of helium = 4 grams
Therefore:
mass of 13 moles of helium = 13*4 = 52 grams</span>
Answer:
m=4 g Ca
M=ArCa+ArO=56 g/mol
Ca+O2-2CaO
nCa= m/M= 4/40=0.1 moles of Ca
the ratio of moles: 1 mole Ca:2 moles CaO
0.1 moles Ca =0.2 moles CaO
n=m/M
m=n×M
m=0.2×56=11.2 g CaO
Explanation:
Work done = force * perpendicular distance
= 1 * 0.01 = 0.01 joules
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