Answer:
There are three possible chemical equations for the combustion of sulfur:
- 2S (s) + O₂ (g) → 2SO (g)
- 2S (s) + 3O₂ (g) → 2SO₃ (g)
Explanation:
<em>Combustion</em> is a reaction with oxygen. The products of the reaction are oxides, and energy is released in the form of heat and light.
<em>Sulfur</em> iis a nonmetal, so the oxide formed is a nonmetal oxide.
The most common oxidation numbers of sulfur are -2, + 2, + 4, and + 6.
The combination of sulfur with oxygen may be only with the positive oxidation numbers (+2, + 4, and +6).
Then you have three different equations for sulfur combustion:
<u>1) Oxidation number +2:</u>
Which when balanced is: 2S(g) + O₂(g) → 2SO(g)
<u>2) Oxitation number +4:</u>
That equation is already balanced.
<u>3) Oxidation number +6:</u>
Which when balanced is: 2S(s) + 3O₂(g) → 2SO₃(g)
Answer:
D. Ar.
Explanation:
The<em> </em><em>electron configuration</em><em> of the atom reflects how the electrons are distributed among the various atomic orbitals</em>. Just as for neutral atoms, we use the Pauli exclusion principle and Hund’s rule in writing the ground-state electron configurations of cations and anions.
<u>Ions formed from atoms of most representative elements have the noble-gas outer electron configuration of ns²np⁶.</u> In the formation of a cation from the atom of a representative element, one or more electrons are removed from the highest occupied n shell. The electron configuration of calcium and its ion is as follows:
Ca: [Ar]4s² Ca²⁺ : [Ar]
Scientist can come to different conclusions based off the same data.
Answer: 0.027837938656318
Explanation: Because 1 grams FeO is equal to 0.013918969328159 mole.
Answer:
45.2 mL must be meausred for the experiment
Explanation:
The density of the acetic acid is 1.105 g/mL, so this data gives the information about how many grams are contained in 1mL of volume.
Notice that 1 mL = 1 cm³
Acetic acid Density = Acetic acid mass / acetic acid volume
1.105 g/mL = 50 g / acetic acid volume
Acetic acid volume = 50 g / 1.105g/mL ⇒ 42.5 mL