The cations has positive charges that are metals while the anions have negative charges that are non-metals. Upon reaction, there is an exchange in charges that are reflected in the subscripts of the atoms. In this case, compound AX2 must have a cation, A belonging to group 2 A with +2 charge and anion, X belonging to Group 7A with -1 charge. Answer is D.
Answer:

Explanation:
To solve this problem, we can use the Combined Gas Laws:

Data:
p₁ = 2.02 atm; V₁ = 736 mL; n₁ = n₁; T₁ = 1 °C
p₂ = ?; V₂ = 416 mL; n₂ = n₁; T₂ = 82 °C
Calculations:
(a) Convert the temperatures to kelvins
T₁ = ( 1 + 273.15) K = 274.15 K
T₂ = (82 + 273.15) K = 355.15 K
(b) Calculate the new pressure

U can assume that riding the bus is a faster way to get to school because it is capable of a faster speed than a bicycle
I think the answer is Endothermic. Since the question says "absorbs," endo means to "go in" sort of and exo means to exit.
exo = exit
endo = enter
(A trick my teacher taught us)
Sorry if I'm wrong, hope I helped. :)