Answer:
last option
Step-by-step explanation:
To prove that ΔEFG is also a right triangle, you must prove that KL = EF so that in ΔKLM c² = a² + b² which would make ΔEFG a right triangle.
Answer:
Step-by-step explanation:
f(x)= (x - 3)(x - 5)
f(x) = x^2 - 5x - 3x + 15
f(x) = x^2 - 8x + 15
Answer is A
No, Yes, No, Yes
using the laws of exponents
(1)
(
)³ = 
4³ × 4³ = 
≠
→ No
(2)
(
)^4 = 
×
=
→ Yes
(3)
= (6 × 3 )^8 =
×
≠
×
→ No
(4)
= (4 × 5 )³ = 4³ × 5³ → Yes
The radius of the circle exists approximately 4.95 feet.
<h3>How to estimate the radius of the circle?</h3>
Given the area of the square as A = 98 ft²
The side length of the square choice is equivalent to the diameter of the circle.
First, we must obtain the length of the square.
Area of a square 
98 = L²
L = √98
L = 9.89 ft
Thus the diameter of the circle exists at 9.89 ft
radius = diameter/2
radius = 9.89/2
radius ≈ 4.95 feet
Therefore the radius of the circle exists approximately 4.95 feet.
To learn more about the radius of circle refer to:
brainly.com/question/19568457
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Depends of the size of the quadrilateral in relation to the circle, but otherwise, yes