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tatyana61 [14]
3 years ago
12

A 6 ft tall tent standing next to a cardboard box casts a 15 ft shadow. if the cardboard box casts a shadow that is 6 ft long th

en how tall is it, and explain
Mathematics
1 answer:
ohaa [14]3 years ago
4 0
What we know is that a 6 foot tall tent casts a 15 foot shadow. Lets represent that given this way: 6 = 15
So, the unknown (y), or what we want to know, is how tall the cardboard box if it has a 6 foot long shadow (noticeably the same height as the tent):
y = 6

6 = 15
y = 6

(6 x 6) / 15 = y
36 / 15 = y
2.4 = y

The height of the cardboard box is 2.4 feet.
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Step-by-step explanation:

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A baseball player had 4 hits in 8 games. At this rate, how many hits will the baseball player have in the next 28 games?
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The common ratio of the given geometric sequence is the number that is multiplied to the first term in order to get the second term. Consequently, this is also the number multiplied to the second term to get the third term. This cycle goes on and on until a certain term is acquired. In this item, the common ratio r is,

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In a volleyball game, a player on one team spikes the ball over the net when the ball is 10 feet above the court. The spike driv
Fynjy0 [20]

Answer:

4.75 seconds

Step-by-step explanation:

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Upward initial velocity given = 55 feet per second

Value of g ( acceleration due to gravity) = 32.2 feet per s²

Motion of the ball:

The ball first goes vertically upwards, gravity decelerates the body and it momentarily comes to rest at a point in its upward trajectory, which is the point of maximum height. From this point, to the ground, the ball behaves as a freely dropped body.

Till the ball reaches its maximum height:

u = + 55

v = 0 ( final velocity is zero)

a = - 32.2 (since it is deceleration)

we know that <em>v = u + at </em>

⇒    0 = 55 - 32.2t

⇒  t = 1.7 s

Also , we have <em>s = ut + (1/2)at²</em>

Here, s is the maximum height from the point where ball is thrown

So,     s = 55(1.7) - (0.5)(32.2)(1.7)(1.7)

⇒ s = 140 feet

So at a height of 140 feet + 10 feet (initial height) = 150 feet, the ball acts as a freely dropped body.

Here,      u = 0

               a = +32.2

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<em>s = ut + (1/2)at²</em>

⇒  150 = 0.5 ( 32.2) (t²)

⇒  t² = 300/32.2 = 9.31

⇒ t = 3.05 sec

So total time = 1.7 + 3.05 = 4.75 seconds

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