I assume that the equation you mean is below:

To find roots for this equation, we have to get rid of the denominator. We can do by multiplying both sides by 3.

Factor w-term out (common factor)

Answer
- The roots of quadratic equation are 0,-3
Step-by-step explanation:
Solve for xsin3⁡x+cos3⁡x=1" role="presentation" style="margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; box-sizing: inherit; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">xsin3x+cos3x=1xsin3x+cos3x=1
sin3⁡x+cos3⁡x=1(sin⁡x+cos⁡x)(sin2⁡x−sin⁡x⋅cos⁡x+cos2⁡x)=1(sin⁡x+cos⁡x)(1−sin⁡x⋅cos⁡x)=1" role="presentation" style="margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; box-sizing: inherit; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">sin3x+cos3x=1(sinx+cosx)(sin2x−sinx⋅cosx+cos2x)=1(sinx+cosx)(1−sinx⋅cosx)=1
Answer:
-8 or -1
Step-by-step explanation:
x*2+9x+8=0
(x+8)(x+1)=0
x+8=0 or x+1=0
x= -8 or x= -1
Answer:Frederick county:2.5x+15,Montgomery county:3x+10
Step-by-step explanation: