Find the circumferences of both circles
2 answers:
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Answer:
Proved CA=CB
Step-by-step explanation:
Given,
In ΔABC, CP is perpendicular to AB.
And CP bisects AB.
So, AP=PB and ∠CPA=∠CPB=90°
The figure of the triangle is in the attachment.
Now, In ΔACP and ΔBCP.
AP = PB(given)
∠CPA = ∠CPB = 90°(perpendicular)
CP = CP(common)
So, By Side-Angle-Side congruence property;
ΔACP ≅ ΔBCP
According to the property of congruence;
"If two triangles are congruent to each other then their corresponding sides are also equal."
Therefore, CA = CB (corresponding side of congruent triangle)
CA = CB Hence Proved
