Name two consecutive odd integers that have a sum of 20??

In New York State, the minimum wage has grownexponentially. In 1966, the minimum wage was$1.25 an hour and in 2015, it was $8.75

Alona [7]

The Solution.

In 1966, which is the initial year(t); t = 0, and minimum wage(y), y = $1.25

Similarly.

In 2015, t = 49 years , (that is, 1966 to 2015), and y = $8.75

The rate of growth to the nearest percent is

$\text{Rate of growth =}\frac{y_2-y_1}{t_2-t_1}\times100$ $\begin{gathered} \text{Where y}_2=8.75,t_2=49\text{ years} \\ y_1=\text{ \$1.25},t_1=0 \end{gathered}$

Substituting into the formula above, we get

$\text{Rate of growth =}\frac{8.75-1.25}{49-0}\times100$ $\text{Rate of growth = }\frac{7.5}{49}\times100=15.31\approx15\text{ \%}$

Hence, the correct answer is 15%

8 0

1 year ago

The dot plot shows the number of hours each week that students in after-school sports spent at practice. Which describes the spr

blondinia [14]

Answer:A I just took the test thing

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Fraction word problems Your strip of paper represents one lap on a track. Three students ran a relay and took turns running equa

artcher [175]

Answer:

A quarter $(\dfrac{1}{4})$ of one lap of the track.

Step-by-step explanation:

Three students ran ran a relay and took turns running equal parts of the track.

The race was three-fourths of a lap long.

Let the length of one lap of the track=x

The length of the race $=\frac{3}{4}x$

Since each of the students ran equal part,

Length run by each student

$=\dfrac{3}{4}x \div 3\\=\dfrac{3}{4}x X \dfrac{1}{3}\\=\dfrac{1}{4}x$

Therefore, each student ran a quarter $(\dfrac{1}{4})$ of one lap of the track.

5 0

3 years ago

A teacher is evaluating how students in her first class did on an assessment versus her last class. The box plots show the resul

MrMuchimi

Answer:

The time a student learns mathematics is important for their score

Step-by-step explanation:

Observe the boxes diagrams. Where the horizontal axis represents the score obtained by the students in the test.

The vertical lines that divide the boxes in two represent the value of the median.

The median is the value that divides 50% of the data.

For the class of the morning the value of the median is 50 points, with a maximum value of 80 and a minimum value of 10.

For the afternoon class, the median value is 65 points with a minimum value of 30 and a maximum value of 100.

This indicates that in general, the highest number of high scores were obtained in the afternoon class.

Therefore it can be said that the time a student learns mathematics is important for their score

4 0

3 years ago

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Expand (x-2) (x-1). Must be in polynomial form.

Ludmilka [50]

To expand two terms such as these, we can use the method called FOIL (stands for First, Outer, Inner, Last). Here is what I mean:

We have two terms: (x - 2)(x - 1)

We should first multiply the First two terms of each term in order to complete the F stage:

(x)*(x) = $x^{2}$

So then, we take the two outer terms and multiply them together to complete the O stage:

(x)*(-1) = -x

So far we have two things that we have calculated; at the end of the FOIL process we will have four.

To keep going with the FOIL, we now multiply the two inner terms to complete the I stage:

(-2)*(x) = -2x

Last but not least, we need to complete the L stage - so we multiply the two last terms of each term:

(-2)*(-1) = 2

Now that we have our four terms, let us add them together and combine like terms:

$x^{2} + (-x) + (-2x) + 2$

Since -x and -2x both have the x portion in common and they are added together, we can add them to create one single term:

-x + (-2x) = -3x

So now that we have our terms completed, we can combine into one polynomial equation:

$x^{2} + (-3x) + 2$ or $x^{2} -3x+2$

6 0

3 years ago